大约有 12,000 项符合查询结果（耗时：0.0326秒） [XML]
Undefined reference to static constexpr char[]
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Add to your cpp file:
constexpr char foo::baz[];
Reason: You have to provide the definition of the static member as well as the declaration. The declaration and the initializer go inside the class definition, but the member definition has to be separate.
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Elasticsearch query to return all records
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I think lucene syntax is supported so:
http://localhost:9200/foo/_search?pretty=true&q=*:*
size defaults to 10, so you may also need &size=BIGNUMBER to get more than 10 items. (where BIGNUMBER equals a number you believe is bigger than your dataset)
BUT, elasticsearch documen...
How do you add an array to another array in Ruby and not end up with a multi-dimensional result?
...ng place -- it flattens its receiver, so you could use it to turn [1, 2, ['foo', 'bar']] into [1,2,'foo','bar'].
I'm doubtless forgetting some approaches, but you can concatenate:
a1.concat a2
a1 + a2 # creates a new array, as does a1 += a2
or prepend/append:
a1.push(*a2) #...
MySQL search and replace some text in a field
...name and field in question:
UPDATE table_name SET field = REPLACE(field, 'foo', 'bar') WHERE INSTR(field, 'foo') > 0;
REPLACE (string functions)
INSTR (string functions)
share
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Can I get JSON to load into an OrderedDict?
...> json.JSONDecoder(object_pairs_hook=collections.OrderedDict).decode('{"foo":1, "bar": 2}')
OrderedDict([('foo', 1), ('bar', 2)])
>>>
You can pass this parameter to json.loads (if you don't need a Decoder instance for other purposes) like so:
>>> import json
>>> fro...
How does variable assignment work in JavaScript?
...b = {};
a and b are now pointers to the same object. So when you do:
a.foo = 'bar';
It sets b.foo as well since a and b point to the same object.
However!
If you do this instead:
a = 'bar';
you are saying that a points to a different object now. This has no effect on what a pointed to be...
Parse query string in JavaScript [duplicate]
...mpire State Building&spaces=these+are+pluses';
tests['with equals'] = 'foo=bar&baz=quux&equals=with=extra=equals&grault=garply';
tests['no value'] = 'foo=bar&baz=&qux=quux';
tests['value omit'] = 'foo=bar&baz&qux=quux';
var $output = document.getElementById('output')...
Building big, immutable objects without using constructors having long parameter lists
... would help you.
It would look like this (purely made up example):
final Foo immutable = FooFactory.create()
.whereRangeConstraintsAre(100,300)
.withColor(Color.BLUE)
.withArea(234)
.withInterspacing(12)
.build();
I wrote "CORRECTLY DONE" in bold because most Java programmers...
What is meant with “const” at end of function declaration? [duplicate]
...tion as a normal function taking an implicit this pointer. So a method int Foo::Bar(int random_arg) (without the const at the end) results in a function like int Foo_Bar(Foo* this, int random_arg), and a call such as Foo f; f.Bar(4) will internally correspond to something like Foo f; Foo_Bar(&f,...
How to get a variable name as a string in PHP?
...ad. So the identity comparison yields true for equals scalar values ($a = 'foo'; $b = 'foo'; assert($a === $b);)?
– Argelbargel
Nov 1 '08 at 0:46
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