大约有 42,000 项符合查询结果(耗时:0.0421秒) [XML]

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List of lists changes reflected across sublists unexpectedly

... 593 When you write [x]*3 you get, essentially, the list [x, x, x]. That is, a list with 3 references...
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Convert list of dictionaries to a pandas DataFrame

...24 cs95 231k6060 gold badges390390 silver badges455455 bronze badges answered Dec 17 '13 at 15:35 jorisjoris ...
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xkcd style graphs in MATLAB

...t a transformation. %# define plot data x = 1:0.1:10; y1 = sin(x).*exp(-x/3) + 3; y2 = 3*exp(-(x-7).^2/2) + 1; %# plot fh = figure('color','w'); hold on plot(x,y1,'b','lineWidth',3); plot(x,y2,'w','lineWidth',7); plot(x,y2,'r','lineWidth',3); xlim([0.95 10]) ylim([0 5]) set(gca,'fontName','Comic ...
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Eclipse RCP Plug-in开发自学教程(Eclipse3.6) - 文档下载 - 清泛网 - ...

Eclipse RCP Plug-in开发自学教程(Eclipse3.6) Eclipse RCP Plug-in本教程素材来源于网络,经过本人的整理、添加以及部分的重写,将原有的Eclipse3.3本的一些内容完全迁移到Eclipse3.6本上来。基于开源以...本教程素材来源于网络,经...
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How do I sort one vector based on values of another

... | edited Oct 15 '09 at 0:31 answered Oct 14 '09 at 21:47 I...
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How does java do modulus calculations with negative numbers?

Am I doing modulus wrong? Because in Java -13 % 64 is supposed to evaluate to -13 but I get 51 . 14 Answers ...
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Why does [5,6,8,7][1,2] = 8 in JavaScript?

... 3 Answers 3 Active ...
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Why does Math.Round(2.5) return 2 instead of 3?

...ounding) Round(Double) / Round(Double, MidpointRounding) Round(Decimal, Int32) / Round(Decimal, Int32, MidpointRounding) Round(Double, Int32) / Round(Double, Int32, MidpointRounding) Whether this default was well chosen or not is a different matter. (MidpointRounding was only introduced in .NET 2....
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What is Weak Head Normal Form?

...re not in normal form: 1 + 2 -- we could evaluate this to 3 (\x -> x + 1) 2 -- we could apply the function "he" ++ "llo" -- we could apply the (++) (1 + 1, 2 + 2) -- we could evaluate 1 + 1 and 2 + 2 Weak head normal form An expression in weak head normal ...
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Use a list of values to select rows from a pandas dataframe [duplicate]

... 1273 You can use isin method: In [1]: df = pd.DataFrame({'A': [5,6,3,4], 'B': [1,2,3,5]}) In [2]: d...