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How to split a string and assign it to variables
In Python it is possible to split a string and assign it to variables:
9 Answers
9
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Find the files existing in one directory but not in the other [closed]
...nd produce unnecessarily long output for large directories, I wrote my own Python script to compare two folders.
Unlike many other solutions, it doesn't compare contents of the files. Also it doesn't go inside subdirectories which are missing in another directory. So the output is quite concise and...
Parse date string and change format
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In python 3.x needs to install python-dateutil pip install python-dateutil
– AB Abhi
Aug 26 '19 at 15:19
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How to compare times in Python?
I see that date comparisons can be done and there's also datetime.timedelta() , but I'm struggling to find out how to check if the current time ( datetime.datetime.now() ) is earlier, later or the same than a specified time (e.g. 8am) regardless of the date.
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How to access outer class from an inner class?
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Hmm, Python is friskier than Java/C++... see my answer below. If we're splitting hairs, which we usually are, I couldn't really tell you whether my "nested class within method" counts as an inner class. At this point, though, I ...
Find the most common element in a list
What is an efficient way to find the most common element in a Python list?
21 Answers
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Uncaught Error: SECURITY_ERR: DOM Exception 18 when I try to set a cookie
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Pro tip: if you have Python installed, simply type python -m SimpleHTTPServer in the root directory of your site, and find it hosted at localhost:8000.
– Thomas
Sep 4 '11 at 17:00
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Check list of words in another string [duplicate]
I can do such thing in python:
4 Answers
4
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Count number of occurrences of a given substring in a string
... count the number of times a given substring is present within a string in Python?
35 Answers
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How to get first element in a list of tuples?
... print list(unzipped[0])
[1, 2]
Edit (@BradSolomon):
The above works for Python 2.x, where zip returns a list.
In Python 3.x, zip returns an iterator and the following is equivalent to the above:
>>> print(list(list(zip(*inpt))[0]))
[1, 2]
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