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Appinventor 音效调用播放后没有声音？ - App应用开发 - 清泛IT社区，为创新赋能！
...发现调用播放后，又调用了停止方法，导致的声音不播放问题，去掉即可。
当然如果因为音频文件损坏等原因，也可能无法正常播放，这时可以先去资源区，点击隐私文件，菜单中选择预览，可以预览播放，事先检查好确保...
how to disable DIV element and everything inside [duplicate]
...
pointer-events: none;
opacity: 0.4;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.2/jquery.min.js"></script>
<div id="div1">
<div id="div2" onclick="alert('Hello')">Click me</div>
<input type="text" value="SAH Compute...
How do I turn a C# object into a JSON string in .NET?
...erialization. Provides serialization and deserialization functionality for AJAX-enabled applications."
– Protector one
Mar 17 '17 at 9:53
...
How to add an Access-Control-Allow-Origin header
...
This solution is also valid for cross domain .ajax requests !! Nice!
– Isaac
Dec 14 '11 at 15:20
3
...
How to enable or disable an anchor using jQuery?
...n disable temporarily an anchor until e.g. the javascript is finished with ajax call or some calculations. If we do not disable it, then we can quickly click it a few times, which is undesirable...
$('a').live('click', function () {
var anchor = $(this);
if (anchor.data("disabled")) {
...
Chrome: Uncaught SyntaxError: Unexpected end of input
...
The issue for me was that I was doing $.ajax with dataType: "json" for a POST request that was returning an HTTP 201 (created) and no request body. The fix was to simply remove that key/value.
...
Convert javascript array to string
....push(str);
});
console.log(blkstr.join(", "));
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
(output will appear in the dev console)
As Felix mentioned, each() is just iterating the array, nothing more.
...
How to make script execution wait until jquery is loaded
... for javascript.
Use this:
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"></script>
<script type="text/javascript" src="../Scripts/jquery.dropdownPlain.js"></script>
<script type="text/javascript" src="../Scripts/fac...
Is well formed without a ?
...
To be able to submit form data to a server (Ajax aside).
– Ludovic Kuty
Sep 9 '13 at 8:07
5
...
Get attribute name value of
...t field. Just cut and past whole script for it to work!
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js" type="text/javascript"></script>
<script>
$(document).ready(function() {
$('.mytarget').change(function() {
var name1 = $(this).attr("name");
alert(nam...