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T-SQL datetime rounded to nearest minute and nearest hours with using functions
In SQL server 2008, I would like to get datetime column rounded to nearest hour and nearest minute preferably with existing functions in 2008.
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Matplotlib - global legend and title aside subplots
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edited Mar 13 at 17:30
answered Feb 10 '12 at 0:47
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How do I install the OpenSSL libraries on Ubuntu?
I'm trying to build some code on Ubuntu 10.04 LTS that uses OpenSSL 1.0.0. When I run make, it invokes g++ with the "-lssl" option. The source includes:
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Convert list of dictionaries to a pandas DataFrame
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1044
Supposing d is your list of dicts, simply:
df = pd.DataFrame(d)
Note: this does not work with...
Create an index on a huge MySQL production table without table locking
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[2017] Update: MySQL 5.6 has support for online index updates
https://dev.mysql.com/doc/refman/8.0/en/innodb-online-ddl-operations.html#online-ddl-index-syntax-notes
In MySQL 5.6 and higher, the table remains available for...
What is a regular expression for a MAC Address?
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The standard (IEEE 802) format for
printing MAC-48 addresses in
human-friendly form is six groups of
two hexadecimal digits, separated by
hyphens - or colons :.
So:
^([0-9A-Fa-f]{2}[:-]){5}([0-9A-Fa-f]{2})$
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How can I replace a regex substring match in Javascript?
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140
var str = 'asd-0.testing';
var regex = /(asd-)\d(\.\w+)/;
str = str.replace(regex, "$11$2");
c...
How to use sed to replace only the first occurrence in a file?
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or, if you prefer: Editor's note: works with GNU sed only.
sed '0,/foo/s//bar/' file
Source
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Regex how to match an optional character
...e letter optional. {1} is redundant. (Of course you could also write [A-Z]{0,1} which would mean the same, but that's what the ? is there for.)
You could improve your regex to
^([0-9]{5})+\s+([A-Z]?)\s+([A-Z])([0-9]{3})([0-9]{3})([A-Z]{3})([A-Z]{3})\s+([A-Z])[0-9]{3}([0-9]{4})([0-9]{2})([0-9]{2})
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How to determine if a point is in a 2D triangle? [closed]
... d2 = sign(pt, v2, v3);
d3 = sign(pt, v3, v1);
has_neg = (d1 < 0) || (d2 < 0) || (d3 < 0);
has_pos = (d1 > 0) || (d2 > 0) || (d3 > 0);
return !(has_neg && has_pos);
}
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