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Create an index on a huge MySQL production table without table locking
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[2017] Update: MySQL 5.6 has support for online index updates
https://dev.mysql.com/doc/refman/8.0/en/innodb-online-ddl-operations.html#online-ddl-index-syntax-notes
In MySQL 5.6 and higher, the table remains available for...
Why does Lua have no “continue” statement?
...Lua 5.2 the best workaround is to use goto:
-- prints odd numbers in [|1,10|]
for i=1,10 do
if i % 2 == 0 then goto continue end
print(i)
::continue::
end
This is supported in LuaJIT since version 2.0.1
share
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Fast Linux File Count for a large number of files
...in a particular directory when there are a very large number of files ( > 100,000).
18 Answers
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php中json_decode()和json_encode()的使用方法 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...de()和json_encode()的使用方法1.json_decode()json_decode(PHP 5 >= 5.2.0, PECL json >= 1.2.0)json_decode — 对 JSON 格式的字符串进行编码说明mixed jso...1.json_decode()
(PHP 5 >= 5.2.0, PECL json >= 1.2.0)
对 JSON 格式的字符串进行编码
说明:
mixed json_decode ...
Compare two DataFrames and output their differences side-by-side
... rows are empty*:
In [21]: ne = (df1 != df2).any(1)
In [22]: ne
Out[22]:
0 False
1 True
2 True
dtype: bool
Then we can see which entries have changed:
In [23]: ne_stacked = (df1 != df2).stack()
In [24]: changed = ne_stacked[ne_stacked]
In [25]: changed.index.names = ['id', 'col']
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Given an RGB value, how do I create a tint (or shade)?
Given an RGB value, like 168, 0, 255 , how do I create tints (make it lighter) and shades (make it darker) of the color?
3...
Javascript and regex: split string and keep the separator
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106
Use (positive) lookahead so that the regular expression asserts that the special character exis...
How to reshape data from long to wide format
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answered May 4 '11 at 23:20
ChaseChase
59.5k1515 gold badges131131 silver badges157157 bronze badges
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Find element's index in pandas Series
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10 Answers
10
Active
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Regex to validate password strength
...itive look ahead assertions:
^(?=.*[A-Z].*[A-Z])(?=.*[!@#$&*])(?=.*[0-9].*[0-9])(?=.*[a-z].*[a-z].*[a-z]).{8}$
Rubular link
Explanation:
^ Start anchor
(?=.*[A-Z].*[A-Z]) Ensure string has two uppercase letters.
(?=.*[!@#$&*]) Ensure string ha...
