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How does type Dynamic work and how to use it?
...me: String) = name
}
scala> val d = new DynImpl
d: DynImpl = DynImpl@6040af64
scala> d.foo
res37: String = foo
scala> d.bar
res38: String = bar
scala> d.selectDynamic("foo")
res54: String = foo
As one can see, it is also possible to call the dynamic methods explicitly.
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answered Apr 30 '10 at 10:47
AdaTheDevAdaTheDev
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NicolasNicolas
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...e"
– Juan Saravia
Jan 30 '15 at 12:04
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