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C#位运算符（C#按位与、按位或 等） - 更多技术 - 清泛网 - 专注C/C++及内核技术
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~a
&
位逻辑与运算
2
a & b
|
位逻辑或运算
2
a | b
^
位逻辑异或运算
2
a ^ b
<<
位左移运算
2
a<<4
>>
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Does delete on a pointer to a subclass call the base class destructor?
... A is instantiated and stored as a pointer field in another class ( class B .
11 Answers
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How to merge dictionaries of dictionaries?
... message when things are inconsistent, while correctly accepting duplicate but consistent entries (something no other answer here does....)
assuming you don't have huge numbers of entries a recursive function is easiest:
def merge(a, b, path=None):
"merges b into a"
if path is None: path =...
R and version control for the solo data analyst
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I feel the answer to your question is a resounding yes- the benefits of managing your files with a version control system far outweigh the costs of implementing such a system.
I will try to respond in detail to some of the points you raised:
Backup: I have a backup ...
Least common multiple for 3 or more numbers
How do you calculate the least common multiple of multiple numbers?
31 Answers
31
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How to swap two variables in JavaScript
I have this two variables:
27 Answers
27
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How do I extract a sub-hash from a hash?
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If you specifically want the method to return the extracted elements but h1 to remain the same:
h1 = {:a => :A, :b => :B, :c => :C, :d => :D}
h2 = h1.select {|key, value| [:b, :d, :e, :f].include?(key) } # => {:b=>:B, :d=>:D}
h1 = Hash[h1.to_a - h2.to_a] # => {:a=>...
Using jQuery to compare two arrays of Javascript objects
I have two arrays of JavaScript Objects that I'd like to compare to see if they are the same. The objects may not (and most likely will not) be in the same order in each array. Each array shouldn't have any more than 10 objects. I thought jQuery might have an elegant solution to this problem, but I ...
Functions that return a function
... with this concept of 'Functions that return functions'. I'm referring the book 'Object Oriented Javascript' by Stoyan Stefanov.
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Multiple aggregations of the same column using pandas GroupBy.agg()
Is there a pandas built-in way to apply two different aggregating functions f1, f2 to the same column df["returns"] , without having to call agg() multiple times?
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