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How to get a function name as a string?
In Python, how do I get a function name as a string, without calling the function?
12 Answers
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How to split a string and assign it to variables
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I like Go but I wouldn't call this flexible :D
– Pijusn
May 25 '17 at 4:27
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Why aren't variables declared in “try” in scope in “catch” or “finally”?
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edited Oct 15 '17 at 1:32
Timo Tijhof
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The input is not a valid Base-64 string as it contains a non-base 64 character
...nes. But is this a concrete solution ? i mean how can i guarantee that for all the files this will be the character to be replaced ?
– Rohit Verma
Feb 27 '13 at 14:52
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Why doesn't GCC optimize a*a*a*a*a*a to (a*a*a)*(a*a*a)?
...scientific application. One thing I noticed is that GCC will optimize the call pow(a,2) by compiling it into a*a , but the call pow(a,6) is not optimized and will actually call the library function pow , which greatly slows down the performance. (In contrast, Intel C++ Compiler , executable ...
How can you get the Manifest Version number from the App's (Layout) XML variables?
...ntext.getPackageName(), 0).versionName;
Either of these solutions would allow for placing the version name in XML. Unfortunately there isn't a nice simple solution, like android.R.string.version or something like that.
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Find all packages installed with easy_install/pip?
Is there a way to find all Python PyPI packages that were installed with easy_install or pip? I mean, excluding everything that was/is installed with the distributions tools (in this case apt-get on Debian).
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How do I add the contents of an iterable to a set?
What is the "one [...] obvious way" to add all items of an iterable to an existing set ?
6 Answers
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Can't find the PostgreSQL client library (libpq)
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answered Jan 28 '15 at 19:32
etusmetusm
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How do I get the computer name in .NET
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@tvanfosson All of these three get me the server name and not the clients machine which is accessing the page. Is this how it works? or am I doing something incorrectly. I would like to get the clients machine, and not the server. I am u...