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Parse JSON String into a Particular Object Prototype in JavaScript
I know how to parse a JSON String and turn it into a JavaScript Object.
You can use JSON.parse() in modern browsers (and IE9+).
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Convert a python dict to a string and back
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The json module is a good solution here. It has the advantages over pickle that it only produces plain text output, and is cross-platform and cross-version.
import json
json.dumps(dict)
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The 'json' native gem requires installed build tools
...86-mingw32] installed on my windows 7 machine. Now I tried to install the JSON gem using the command, "gem install json" and got the following error.
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How do I cast a JSON object to a typescript class
I read a JSON object from a remote REST server. This JSON object has all the properties of a typescript class (by design). How do I cast that received JSON object to a type var?
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JSON: why are forward slashes escaped?
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JSON doesn't require you to do that, it allows you to do that. It also allows you to use "\u0061" for "A", but it's not required. Allowing \/ helps when embedding JSON in a <script> tag, which doesn't allow </ inside...
Maven: missing net.sf.json-lib
I found net.sf.json-lib in the central repository . Copy-pasted the dependency (with version 2.3), and then when I build I get this error:
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JAX-RS — How to return JSON and HTTP status code together?
...ST web app (NetBeans 6.9, JAX-RS, TopLink Essentials) and trying to return JSON and HTTP status code. I have code ready and working that returns JSON when the HTTP GET method is called from the client. Essentially:
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Making a property deserialize but not serialize with json.net
...me configuration files which were generated by serializing C# objects with Json.net.
10 Answers
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How do I deserialize a JSON string into an NSDictionary? (For iOS 5+)
In my iOS 5 app, I have an NSString that contains a JSON string. I would like to deserialize that JSON string representation into a native NSDictionary object.
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How to use the 'main' parameter in package.json?
...dy. However, still having doubts about the 'main' parameter in the package.json of a Node project.
7 Answers
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