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Bootstrap dropdown sub menu missing
...dn't figure out how to put a sub menu class. Even there is no class in css and even the new docs don't say anything about it
...
Move capture in lambda
...ref( T && x )
{
return rref_impl<T>{ std::move(x) };
}
And here's a test case for that function that ran successfully on my gcc 4.7.3.
int main()
{
std::unique_ptr<int> p{new int(0)};
auto rref = make_rref( std::move(p) );
auto lambda =
[rref]() mutabl...
Is it possible to get the non-enumerable inherited property names of an object?
...etOwnPropertyNames can get you non-enumerable properties, you can use that and combine it with walking up the prototype chain.
function getAllProperties(obj){
var allProps = []
, curr = obj
do{
var props = Object.getOwnPropertyNames(curr)
props.forEach(function(prop){
...
Constructor of an abstract class in C#
...
Because there might be a standard way you want to instantiate data in the abstract class. That way you can have classes that inherit from that class call the base constructor.
public abstract class A{
private string data;
protected A(string...
Ruby on Rails generates model field:type - what are the options for field:type?
I'm trying to generate a new model and forget the syntax for referencing another model's ID. I'd look it up myself, but I haven't figured out, among all my Ruby on Rails documentation links, how to find the definitive source.
...
Responsive css background images
I have a website (g-floors.eu) and I want to make the background (in css I have defined a bg-image for the content) also responsive. Unfortunately I really don't have any idea on how to do this except for one thing that I can think of but it's quite a workaround. Creating multiple images and then us...
Encrypt Password in Configuration Files? [closed]
I have a program that reads server information from a configuration file and would like to encrypt the password in that configuration that can be read by my program and decrypted.
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javascript set a variable if undefined
I know that I can test for a javascript variable and then define it if it is undefined, but is there not some way of saying
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Is there a more elegant way of adding an item to a Dictionary safely?
... Add if the existence of the key indicates a bug (so you want it to throw) and the indexer otherwise. (It's a bit like the difference between casting and using as for reference conversions.)
If you're using C# 3 and you have a distinct set of keys, you can make this even neater:
var currentViews =...
How to get rid of the 'undeclared selector' warning
...rty if the NSObject instance it's called on supports it. This is the code, and the code works as intended:
12 Answers
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