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Algorithm for classifying words for hangman difficulty levels as “Easy”,“Medium”, or “Hard”
...split()
>>> sorted(list(partition('e', words).items()))
[(0, ['star']), (2, ['mews']), (5, ['even', 'eyes']), (6, ['deed', 'peep'])]
"""
result = defaultdict(list)
for word in words:
key = sum(1 << i for i, letter in enumerate(word) if letter == guess)
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Convert object to JSON in Android
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edited Mar 24 at 6:02
Akshay
2,43233 gold badges3232 silver badges5050 bronze badges
answered Apr...
Gradle alternate to mvn install
...
sdk/build.gradle:
apply plugin: "maven"
group = "foo"
version = "1.0"
example/build.gradle:
repositories {
mavenLocal()
}
dependencies {
compile "foo:sdk:1.0"
}
$sdk> gradle install
$example> gradle build
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Check string for palindrome
...y not just:
public static boolean istPalindrom(char[] word){
int i1 = 0;
int i2 = word.length - 1;
while (i2 > i1) {
if (word[i1] != word[i2]) {
return false;
}
++i1;
--i2;
}
return true;
}
Example:
Input is "andna".
i1 will be 0...
IISExpress Log File Location
... your choice. Following link may help you http://learn.iis.net/page.aspx/870/running-iis-express-from-the-command-line/
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Enter “&” symbol into a text Label in Windows Forms?
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203
Two ways:
Escape it with another ampersand (&&).
Set UseMnemonic for that label to fa...
UITextfield leftView/rightView padding on iOS7
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90
Was just working on this myself and used this solution:
- (CGRect) rightViewRectForBounds:(CGRe...
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gnclmorais
4,36044 gold badges2727 silver badges3838 bronze badges
answered Jun 25 '13 at 21:43
adamdboudreauadamdbo...
What does (x ^ 0x1) != 0 mean?
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The XOR operation (x ^ 0x1) inverts bit 0. So the expression effectively means: if bit 0 of x is 0, or any other bit of x is 1, then the expression is true.
Conversely the expression is false if x == 1.
So the test is the same as:
if (x != 1)
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PHP: Count a stdClass object
...urn the right number when I run the count($obj) function. The object has 30 properties, but the return on the count() function is say 1.
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