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How to normalize a NumPy array to within a certain range?
...
140
audio /= np.max(np.abs(audio),axis=0)
image *= (255.0/image.max())
Using /= and *= allows you ...
Days between two dates? [duplicate]
...er of days:
>>> from datetime import date
>>> a = date(2011,11,24)
>>> b = date(2011,11,17)
>>> a-b
datetime.timedelta(7)
>>> (a-b).days
7
And it works with datetimes too — I think it rounds down to the nearest day:
>>> from datetime import...
python pandas remove duplicate columns
...
409
There's a one line solution to the problem. This applies if some column names are duplicated an...
Is it worth using Python's re.compile?
...
I've had a lot of experience running a compiled regex 1000s of times versus compiling on-the-fly, and have not noticed any perceivable difference. Obviously, this is anecdotal, and certainly not a great argument against compiling, but I've found the difference to be negligible.
...
Array include any value from another array?
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answered Oct 15 '10 at 11:55
NakilonNakilon
31.1k1212 gold badges9494 silver badges125125 bronze badges
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Write bytes to file
I have a hexadecimal string (e.g 0CFE9E69271557822FE715A8B3E564BE ) and I want to write it to a file as bytes. For example,
...
How do I represent a hextile/hex grid in memory?
...ex grids also)
– amitp
Jun 7 '13 at 0:58
I find the blog super confusing, using x,y,z and q,r,s then the implementatio...
How can I get the client's IP address in ASP.NET MVC?
...e
{
szIP = szXForwardedFor;
if (szIP.IndexOf(",") > 0)
{
string [] arIPs = szIP.Split(',');
foreach (string item in arIPs)
{
if (!isPrivateIP(item))
{
return item;
...
Using comparison operators in Scala's pattern matching system
....e. an if and a boolean expression after the pattern:
a match {
case 10 => println("ten")
case x if x > 10 => println("greater than ten")
case _ => println("less than ten")
}
Edit: Note that this is more than superficially different to putting an if after the =>, becaus...
How to calculate a logistic sigmoid function in Python?
... math.exp(-x))
And now you can test it by calling:
>>> sigmoid(0.458)
0.61253961344091512
Update: Note that the above was mainly intended as a straight one-to-one translation of the given expression into Python code. It is not tested or known to be a numerically sound implementation. I...