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How to check if the string is empty?
... answered Mar 5 '12 at 20:10
Andrew ClarkAndrew Clark
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How to use JavaScript variables in jQuery selectors?
...od]();
});
Now you can completely control which element you're targeting and what happens to it via the HTML. For example, you could use data-target=".some-class" and data-method="fadeOut" to fade-out a collection of elements.
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Distinct in Linq based on only one field of the table
...t).Select(x => x.FirstOrDefault());
This will group the table by Text and use the first row from each groups resulting in rows where Text is distinct.
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How to set variable from a SQL query?
...'South Coast')
See this question for the difference between using SELECT and SET in TSQL.
Warning
If this select statement returns multiple values (bad to begin with):
When using SELECT, the variable is assigned the last value that is returned (as womp said), without any error or warning (thi...
Python - use list as function parameters
...is has already been answered perfectly, but since I just came to this page and did not understand immediately I am just going to add a simple but complete example.
def some_func(a_char, a_float, a_something):
print a_char
params = ['a', 3.4, None]
some_func(*params)
>> a
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How do I round a decimal value to 2 decimal places (for output on a page)
...mal currently with .ToString() , it's accurate to like 15 decimal places, and since I'm using it to represent dollars and cents, I only want the output to be 2 decimal places.
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LEFT OUTER joins in Rails 3
...s(:blog).where("users.id IS NULL").select
– Linus Oleander
Dec 1 '11 at 23:15
1
Doesn't select ne...
How do I get the current version of my iOS project in code?
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You can get the version and build numbers as follows:
let version = Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") as! String
let build = Bundle.main.object(forInfoDictionaryKey: kCFBundleVersionKey as String) as! String
o...
Convert list to tuple in Python
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Expanding on eumiro's comment, normally tuple(l) will convert a list l into a tuple:
In [1]: l = [4,5,6]
In [2]: tuple
Out[2]: <type 'tuple'>
In [3]: tuple(l)
Out[3]: (4, 5, 6)
However, if you've redefined tuple to be...
AngularJs ReferenceError: $http is not defined
...'$http', function($scope,$http) {
//$http is working in this
}]);
and It has worked well.
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