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How to run cron job every 2 hours

... Just do: 0 */2 * * * /home/username/test.sh The 0 at the beginning means to run at the 0th minute. (If it were an *, the script would run every minute during every second hour.) Don't forget, you can check syslog to see if it eve...
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List comprehension in Ruby

...1, 2, 3, 4, 5, 6] new_array = some_array.comprehend {|x| x * 3 if x % 2 == 0} puts new_array Prints: 6 12 18 I would probably just do it the way you did though. share | improve this answer ...
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How do I apply CSS3 transition to all properties except background-position?

... Here's a solution that also works on Firefox: transition: all 0.3s ease, background-position 1ms; I made a small demo: http://jsfiddle.net/aWzwh/ share | improve this answer ...
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Is it worth using Python's re.compile?

... I've had a lot of experience running a compiled regex 1000s of times versus compiling on-the-fly, and have not noticed any perceivable difference. Obviously, this is anecdotal, and certainly not a great argument against compiling, but I've found the difference to be negligible. ...
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Determine version of Entity Framework I am using?

...e two versions 1 and 2? And version 2 is referred to as Entity Framework 4.0? 10 Answers ...
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Install dependencies globally and locally using package.json

... | edited Jun 20 at 9:12 Community♦ 111 silver badge answered May 30 '12 at 9:05 ...
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How to center align the cells of a UICollectionView?

... 80 I think you can achieve the single line look by implementing something like this: - (UIEdgeInse...
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Compare if BigDecimal is greater than zero

... It's as simple as: if (value.compareTo(BigDecimal.ZERO) > 0) The documentation for compareTo actually specifies that it will return -1, 0 or 1, but the more general Comparable<T>.compareTo method only guarantees less than zero, zero, or greater than zero for the appropriate ...
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Pandas every nth row

... 207 I'd use iloc, which takes a row/column slice, both based on integer position and following norm...
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Evenly distributing n points on a sphere

...orithm that can give me positions around a sphere for N points (less than 20, probably) that vaguely spreads them out. There's no need for "perfection", but I just need it so none of them are bunched together. ...