大约有 47,000 项符合查询结果(耗时:0.0472秒) [XML]
Check if all elements in a list are identical
..., for Python 2.7 and (only s1, s4, s7, s9 should return True)
s1 = [1] * 5000
s2 = [1] * 4999 + [2]
s3 = [2] + [1]*4999
s4 = [set([9])] * 5000
s5 = [set([9])] * 4999 + [set([10])]
s6 = [set([10])] + [set([9])] * 4999
s7 = [1,1]
s8 = [1,2]
s9 = []
we get
| checkEqual1 | checkEqual2 | checkE...
Principal component analysis in Python
...
|
edited Sep 3 '10 at 11:40
nikow
19.6k66 gold badges4242 silver badges6969 bronze badges
answe...
In Typescript, How to check if a string is Numeric
... edited Feb 13 '18 at 14:19
k0pernikus
35.4k4040 gold badges154154 silver badges266266 bronze badges
answered May 3 '14 at 6:09
...
How do I apply CSS3 transition to all properties except background-position?
...
Here's a solution that also works on Firefox:
transition: all 0.3s ease, background-position 1ms;
I made a small demo: http://jsfiddle.net/aWzwh/
share
|
improve this answer
...
What belongs in an educational tool to demonstrate the unwarranted assumptions people make in C/C++?
... Functions can be called in either order
**/
return 0;
}
share
|
improve this answer
|
follow
|
...
Peak memory usage of a linux/unix process
...
20 Answers
20
Active
...
Splitting a list into N parts of approximately equal length
...ken due to rounding errors. Do not use it!!!
assert len(chunkIt([1,2,3], 10)) == 10 # fails
Here's one that could work:
def chunkIt(seq, num):
avg = len(seq) / float(num)
out = []
last = 0.0
while last < len(seq):
out.append(seq[int(last):int(last + avg)])
...
Using comparison operators in Scala's pattern matching system
....e. an if and a boolean expression after the pattern:
a match {
case 10 => println("ten")
case x if x > 10 => println("greater than ten")
case _ => println("less than ten")
}
Edit: Note that this is more than superficially different to putting an if after the =>, becaus...
How to get the seconds since epoch from the time + date output of gmtime()?
...calendar.timegm().
>>> calendar.timegm(time.gmtime())
1293581619.0
You can turn your string into a time tuple with time.strptime(), which returns a time tuple that you can pass to calendar.timegm():
>>> import calendar
>>> import time
>>> calendar.timegm(time....
What's the algorithm to calculate aspect ratio?
...
203
I gather you're looking for an usable aspect ratio integer:integer solution like 16:9 rather th...
