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Paperclip::Errors::MissingRequiredValidatorError with Rails 4

...ays "MissingRequiredValidatorError" I thought that by updating post_params and giving it :image it would be fine, as both create and update use post_params ...
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How can I search for a commit message on GitHub?

... I've been watching for five minutes and I can't figure out where the mouse goes after it zooms down and to the right. – Kevin Krumwiede Jul 14 '18 at 21:44 ...
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How to make PyCharm always show line numbers

...g to enable line numbers for all files, but I have to always right click and enable this on per file basis. 6 Answers ...
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Converting a Pandas GroupBy output from Series to DataFrame

...taFrame. It has a hierarchical index, though: In [19]: type(g1) Out[19]: pandas.core.frame.DataFrame In [20]: g1.index Out[20]: MultiIndex([('Alice', 'Seattle'), ('Bob', 'Seattle'), ('Mallory', 'Portland'), ('Mallory', 'Seattle')], dtype=object) Perhaps you want something like this? In ...
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Breaking up long strings on multiple lines in Ruby without stripping newlines

... I'm fairly sure that it's not; I tried both undef'ing and redefining String#+ and it doesn't seem like anything is being sent there. – Jessehz May 9 '12 at 22:08 ...
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AttributeError(“'str' object has no attribute 'read'”)

... I don't understand this...how does doing read() solve the problem? The response still doesn't have a read function. Are we supposed to put the string in some object with a read function? – zakdances Au...
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Recursive directory listing in DOS

...oter information try this: dir /s /b (For sure this will work for DOS 6 and later; might have worked prior to that, but I can't recall.) share | improve this answer | foll...
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How can I get name of element with jQuery?

...his).attr('name'); on a class selector $('.jobSelect').change(function() { and I didn't encounter problems. – Ömer An Dec 28 '19 at 8:57 add a comment  |  ...
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What do you call the -> operator in Ruby?

... In Ruby Programming Language ("Methods, Procs, Lambdas, and Closures"), a lambda defined using -> is called lambda literal. succ = ->(x){ x+1 } succ.call(2) The code is equivalent to the following one. succ = lambda { |x| x + 1 } succ.call(2) Informally, I have heard...
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unbound method f() must be called with fibo_ instance as first argument (got classobj instance inste

In Python, I'm trying to run a method in a class and I get an error: 8 Answers 8 ...