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How to get duplicate items from a list using LINQ? [duplicate]
...t; s)
.SelectMany(grp => grp.Skip(1));
Note that this will return all duplicates, so if you only want to know which items are duplicated in the source list, you could apply Distinct to the resulting sequence or use the solution given by Mark Byers.
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How to use ng-repeat without an html element
I need to use ng-repeat (in AngularJS) to list all of the elements in an array.
8 Answers
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jquery IDs with spaces
... so Elliot's answer helps tremendously, whereas glavic's offers no help at all.
– daybreaker
Jun 27 '11 at 18:59
Thank...
How do I fetch only one branch of a remote Git repository?
I'd like to grab a single branch (not all of them) of a remote repository and create a local tracking branch that can track further updates to that remote branch. The other branches in the remote repository are very big, so I'd like to avoid fetching them. How do I do this?
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Why should I prefer single 'await Task.WhenAll' over multiple awaits?
...n case I do not care about the order of task completion and just need them all to complete, should I still use await Task.WhenAll instead of multiple await ? e.g, is DoWork2 below a preferred method to DoWork1 (and why?):
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How can I get nth element from a list?
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Personally I can't comprehend how an at-index accessor that doesn't return a Maybe type is acceptable as idiomatic Haskell. [1,2,3]!!6 will give you a runtime error. It could very easily be avoided if !! had the type [a] -> Int ...
汇编语言超浓缩教程（汇编入门必备） - C/C++ - 清泛网 - 专注C/C++及内核技术
...示原结果，故找一赝品将就着。
Program terminated normally
我们可以用Ｕ命令将十六进制的机器码反汇编（Unassemble）成汇编指令。你将发现每一行右边的汇编指令就是被汇编成相应的机器码，而8086实际上就是以机器码来...
Should arrays be used in C++?
...to use traditional C arrays in C++, or should they be avoided, just like malloc ?
11 Answers
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Which are more performant, CTE or temporary tables?
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Temp tables also allows for Indexes and even Statistics which are sometimes necessary, while a CTE does not.
– CodeCowboyOrg
Sep 4 '14 at 15:30
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Oracle “Partition By” Keyword
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+--------------+---------------+
2) The boss says "Now get me a list of all items, with their brand AND number of items that the respective brand has"
You may try:
SELECT
ITEM_NR
,BRAND
,COUNT(ITEM_ID)
FROM
ITEMS
GROUP BY
BRAND;
But you get:
ORA-00979: no...