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LINQ OrderBy versus ThenBy
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Chris MoschiniChris Moschini
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Uploading base64 encoded Image to Amazon S3 via Node.js
...plain JS?
– Pointi
Apr 13 '18 at 12:32
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Rollback a Git merge
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answered Jul 30 '12 at 13:32
ChristopherChristopher
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SQL Server: Maximum character length of object names
...000/svg\"\u003e\u003cpath d=\"M46.1709 9.17788C46.1709 8.26454 46.2665 7.94324 47.1084 7.58816C47.4091 7.46349 47.7169 7.36433 48.0099 7.26993C48.9099 6.97997 49.672 6.73443 49.672 5.93063C49.672 5.22043 48.9832 4.61182 48.1414 4.61182C47.4335 4.61182 46.7256 4.91628 46.0943 5.50789C45.7307 4.9328 4...
Moq mock method with out specifying input parameter
...000/svg\"\u003e\u003cpath d=\"M46.1709 9.17788C46.1709 8.26454 46.2665 7.94324 47.1084 7.58816C47.4091 7.46349 47.7169 7.36433 48.0099 7.26993C48.9099 6.97997 49.672 6.73443 49.672 5.93063C49.672 5.22043 48.9832 4.61182 48.1414 4.61182C47.4335 4.61182 46.7256 4.91628 46.0943 5.50789C45.7307 4.9328 4...
JSON.parse unexpected character error
...your line below,
JSON.parse(JSON.stringify({"balance":0,"count":0,"time":1323973673061,"firstname":"howard","userId":5383,"localid":1,"freeExpiration":0,"status":false}));
or if you have JSON stored in some variable:
JSON.parse(JSON.stringify(yourJSONobject));
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C# list.Orderby descending
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StriplingWarriorStriplingWarrior
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Reasons that the passed Intent would be NULL in onStartCommand
...000/svg\"\u003e\u003cpath d=\"M46.1709 9.17788C46.1709 8.26454 46.2665 7.94324 47.1084 7.58816C47.4091 7.46349 47.7169 7.36433 48.0099 7.26993C48.9099 6.97997 49.672 6.73443 49.672 5.93063C49.672 5.22043 48.9832 4.61182 48.1414 4.61182C47.4335 4.61182 46.7256 4.91628 46.0943 5.50789C45.7307 4.9328 4...
git: Show index diff in commit message as comment
...riately (red for deleted lines, etc.):
[core]
editor = C:/Windows/system32/notepad.exe -s diff
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Why can't (or doesn't) the compiler optimize a predictable addition loop into a multiplication?
...(if data[c] is 30000, the product would become -1294967296 for the typical 32-bit ints with wrap around, while 100000 times adding 30000 to sum would, if that doesn't overflow, increase sum by 3000000000). Note that the same holds for unsigned quantities, with different numbers, overflow of 100000 *...