大约有 47,000 项符合查询结果（耗时：0.0538秒） [XML]
Pandas every nth row
...
207
I'd use iloc, which takes a row/column slice, both based on integer position and following norm...
How to center align the cells of a UICollectionView?
...
80
I think you can achieve the single line look by implementing something like this:
- (UIEdgeInse...
Is it worth using Python's re.compile?
...
I've had a lot of experience running a compiled regex 1000s of times versus compiling on-the-fly, and have not noticed any perceivable difference. Obviously, this is anecdotal, and certainly not a great argument against compiling, but I've found the difference to be negligible.
...
How do I count the number of occurrences of a char in a String?
...
answered Nov 29 '09 at 22:23
CowanCowan
34.8k1111 gold badges6363 silver badges6363 bronze badges
...
Numpy: Get random set of rows from 2D array
...
200
>>> A = np.random.randint(5, size=(10,3))
>>> A
array([[1, 3, 0],
[3, ...
List comprehension in Ruby
...1, 2, 3, 4, 5, 6]
new_array = some_array.comprehend {|x| x * 3 if x % 2 == 0}
puts new_array
Prints:
6
12
18
I would probably just do it the way you did though.
share
|
improve this answer
...
Compare if BigDecimal is greater than zero
...
It's as simple as:
if (value.compareTo(BigDecimal.ZERO) > 0)
The documentation for compareTo actually specifies that it will return -1, 0 or 1, but the more general Comparable<T>.compareTo method only guarantees less than zero, zero, or greater than zero for the appropriate ...
Are there any O(1/n) algorithms?
...he following one:
def get_faster(list):
how_long = (1 / len(list)) * 100000
sleep(how_long)
Clearly, this function spends less time as the input size grows … at least until some limit, enforced by the hardware (precision of the numbers, minimum of time that sleep can wait, time to proce...
How do I apply CSS3 transition to all properties except background-position?
...
Here's a solution that also works on Firefox:
transition: all 0.3s ease, background-position 1ms;
I made a small demo: http://jsfiddle.net/aWzwh/
share
|
improve this answer
...