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Grep regex NOT containing string
....4.*Has exploded"
patterns[2]="5\.6\.7\.8.*Has died"
patterns[3]="\!9\.10\.11\.12.*Has exploded"
for i in {1..3}
do
grep "${patterns[$i]}" logfile.log
done
should be the the same as
egrep "(1\.2\.3\.4.*Has exploded|5\.6\.7\.8.*Has died)" logfile.log | egrep -v "9\.10\.11\.12.*Has exploded" ...
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edited Sep 11 '16 at 17:54
answered Feb 12 '12 at 20:35
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