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Why doesn't GCC optimize a*a*a*a*a*a to (a*a*a)*(a*a*a)?

...etter not to pass it. – xis Jun 21 '11 at 19:09 21 IIRC C99 allows the compiler to do such "unsaf...
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How to make HTML table cell editable?

...gt; <td>name</td> </tr> <tr> <td>001</td> <td>dog</td> </tr> <tr> <td>002</td> <td>cat</td> </tr> <tr> <td>003</td> <td>pig</td> </tr> ...
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How can I profile Python code line-by-line?

... 1.3 10.4 while 1: 153 50000 69065 1.4 11.4 if Char1Glob == 'A': 154 50000 66354 1.3 10.9 IntLoc = IntLoc - 1 155 50000 67263 1.3 11.1 IntParIO = IntLoc - IntGlob 156 50000 ...
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wkhtmltopdf: cannot connect to X server

... downloading wkhtmltox-linux-amd64_0.12.0-03c001d.tar.xz works for me now. For some reason the latest does not. – chasetheskyforever Jul 17 '14 at 15:35 ...
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Is CSS Turing complete?

...rom { padding: 0; } to { padding: 0; } } /* * 111 110 101 100 011 010 001 000 * 0 1 1 0 1 1 1 0 */ body > input { -webkit-appearance: none; display: block; float: left; border-right: 1px solid #ddd; border-bottom: 1px solid #ddd; padding: 0...
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How to get all possible combinations of a list’s elements?

...ll elements corresponding to a "1". items=abc * mask=### | V 000 -> 001 -> c 010 -> b 011 -> bc 100 -> a 101 -> a c 110 -> ab 111 -> abc Things to consider: This requires that you can call len(...) on items (workaround: if items is something like an iterable like ...
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How does the Java 'for each' loop work?

... 1193 for (Iterator<String> i = someIterable.iterator(); i.hasNext();) { String item = i....
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How do I make my GUI behave well when Windows font scaling is greater than 100%

... answered Nov 28 '11 at 16:10 Warren PWarren P 56k3636 gold badges162162 silver badges293293 bronze badges ...
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How to convert integer timestamp to Python datetime

... @manu-fatto: That does not really matter. x * 0.001 and x / 1e3 are both the same, the difference is in the notation and length (the original one is shorter). For some people it may be clearer to actually divide by the number instead of multiplying by the multiplicative in...
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String concatenation in Ruby

...t;< changes the object on its left hand side, and + doesn't. irb(main):001:0> s = 'a' => "a" irb(main):002:0> s + 'b' => "ab" irb(main):003:0> s => "a" irb(main):004:0> s << 'b' => "ab" irb(main):005:0> s => "ab" ...