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Malloc vs new — different padding
I'm reviewing someone else's C++ code for our project that uses MPI for high-performance computing (10^5 - 10^6 cores). The code is intended to allow for communications between (potentially) different machines on different architectures. He's written a comment that says something along the lines of:...
What is the difference between syntax and semantics in programming languages?
...ference between syntax and semantics in programming languages (like C, C++)?
10 Answers
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Adjusting Eclipse console size
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I had a similar problem with my c++ build console. This is set in Preferences->C/C++->Build->Console
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How do you exit from a void function in C++?
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Which sort algorithm works best on mostly sorted data? [closed]
...into worst case behaviour no matter how your data looks like.
If you're a C++ programmer check your std::sort algorithm. It may already use introspective sort internally.
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Call apply-like function on each row of dataframe with multiple arguments from each row
...s, especially if you come from a procedural programming background such as C++ or C#.
– Contango
Mar 31 '14 at 8:59
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Are std::vector elements guaranteed to be contiguous?
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This was missed from C++98 standard proper but later added as part of a TR. The forthcoming C++0x standard will of course contain this as a requirement.
From n2798 (draft of C++0x):
23.2.6 Class template vector [vector]
1 A vector is a ...
How do I achieve the theoretical maximum of 4 FLOPs per cycle?
... rA = _mm_or_pd(rA,vONE);
rB = _mm_or_pd(rB,vONE);
c++;
}
r0 = _mm_add_pd(r0,r1);
r2 = _mm_add_pd(r2,r3);
r4 = _mm_add_pd(r4,r5);
r6 = _mm_add_pd(r6,r7);
r8 = _mm_add_pd(r8,r9);
rA = _mm_add_pd(rA,rB);
r0 = _mm_add_pd(r0,r2);
r4 = _mm_add...
What's the difference between the 'ref' and 'out' keywords?
... ref is not only applicable to value types. ref/out are like pointers in C/C++, they deal with the memory location of the object (indirectly in C#) instead of the direct object.
– thr
Mar 15 '10 at 6:53
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Simple (non-secure) hash function for JavaScript? [duplicate]
... for (i=0; i<o.length; i++) {
for (c=0; c<r.length; c++) {
r[c] = (r[c] << 13)-(r[c] >> 19);
r[c] += o.charCodeAt(i) << (r[c] % 24);
r[c] = r[c] & r[c];
}
}
for (i=0; i<r.lengt...