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How can I easily view the contents of a datatable or dataview in the immediate window
...Set, expand the quick watch, view the Tables, expand that, then view Table[0] (for example). You will see something like {Table1} in the quick watch, but notice that there is also a magnifying glass icon. Click on that icon and your DataTable will open up in a grid view.
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Check if all elements in a list are identical
..., for Python 2.7 and (only s1, s4, s7, s9 should return True)
s1 = [1] * 5000
s2 = [1] * 4999 + [2]
s3 = [2] + [1]*4999
s4 = [set([9])] * 5000
s5 = [set([9])] * 4999 + [set([10])]
s6 = [set([10])] + [set([9])] * 4999
s7 = [1,1]
s8 = [1,2]
s9 = []
we get
| checkEqual1 | checkEqual2 | checkE...
Calling a Method From a String With the Method's Name in Ruby
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answered Sep 10 '09 at 20:17
Colin GravillColin Gravill
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Pandas every nth row
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207
I'd use iloc, which takes a row/column slice, both based on integer position and following norm...
Replacing NULL with 0 in a SQL server query
...ults for the first three columns I get NULL . How can I replace it with 0 ?
11 Answers
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List all indexes on ElasticSearch server?
...oncise list of all indices in your cluster, call
curl http://localhost:9200/_aliases
this will give you a list of indices and their aliases.
If you want it pretty-printed, add pretty=true:
curl http://localhost:9200/_aliases?pretty=true
The result will look something like this, if your indic...
What's the point of malloc(0)?
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According to the specifications, malloc(0) will return either "a null pointer or a unique pointer that can be successfully passed to free()".
This basically lets you allocate nothing, but still pass the "artist" variable to a call to free() without worry. For pra...
python pandas remove duplicate columns
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409
There's a one line solution to the problem. This applies if some column names are duplicated an...
Should I return EXIT_SUCCESS or 0 from main()?
...eing conflicting answers: should the main routine of a C++ program return 0 or EXIT_SUCCESS ?
8 Answers
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How to normalize a NumPy array to within a certain range?
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140
audio /= np.max(np.abs(audio),axis=0)
image *= (255.0/image.max())
Using /= and *= allows you ...