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Splitting a list into N parts of approximately equal length

...ken due to rounding errors. Do not use it!!! assert len(chunkIt([1,2,3], 10)) == 10 # fails Here's one that could work: def chunkIt(seq, num): avg = len(seq) / float(num) out = [] last = 0.0 while last < len(seq): out.append(seq[int(last):int(last + avg)]) ...
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Using comparison operators in Scala's pattern matching system

....e. an if and a boolean expression after the pattern: a match { case 10 => println("ten") case x if x > 10 => println("greater than ten") case _ => println("less than ten") } Edit: Note that this is more than superficially different to putting an if after the =>, becaus...
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How do I apply CSS3 transition to all properties except background-position?

... Here's a solution that also works on Firefox: transition: all 0.3s ease, background-position 1ms; I made a small demo: http://jsfiddle.net/aWzwh/ share | improve this answer ...
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Peak memory usage of a linux/unix process

... 20 Answers 20 Active ...
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python pandas remove duplicate columns

... 409 There's a one line solution to the problem. This applies if some column names are duplicated an...
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What's the algorithm to calculate aspect ratio?

... 203 I gather you're looking for an usable aspect ratio integer:integer solution like 16:9 rather th...
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How to get the seconds since epoch from the time + date output of gmtime()?

...calendar.timegm(). >>> calendar.timegm(time.gmtime()) 1293581619.0 You can turn your string into a time tuple with time.strptime(), which returns a time tuple that you can pass to calendar.timegm(): >>> import calendar >>> import time >>> calendar.timegm(time....
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How do I represent a hextile/hex grid in memory?

...ex grids also) – amitp Jun 7 '13 at 0:58 I find the blog super confusing, using x,y,z and q,r,s then the implementatio...
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How to compare two colors for similarity/difference

... answered Jan 26 '12 at 14:20 Liudvikas BukysLiudvikas Bukys 5,27033 gold badges2323 silver badges3636 bronze badges ...
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How to calculate a logistic sigmoid function in Python?

... math.exp(-x)) And now you can test it by calling: >>> sigmoid(0.458) 0.61253961344091512 Update: Note that the above was mainly intended as a straight one-to-one translation of the given expression into Python code. It is not tested or known to be a numerically sound implementation. I...