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Why is a round-trip conversion via a string not safe for a double?
...ccccccccccccccd),
/*2*/ I64(0xa3d70a3d70a3d70b),
/*3*/ I64(0x83126e978d4fdf3c),
/*4*/ I64(0xd1b71758e219652e),
/*5*/ I64(0xa7c5ac471b478425),
/*6*/ I64(0x8637bd05af6c69b7),
/*7*/ I64(0xd6bf94d5e57a42be),
/*8*/ I64(0xabcc77118461ceff),
/*9*/ I64(0x89705f4136b4a599),
...
What is the difference between bottom-up and top-down?
... would call fib(100)=fib(99)+fib(98), which would call fib(99)=fib(98)+fib(97), ...etc..., which would call fib(2)=fib(1)+fib(0)=1+0=1. Then it would finally resolve fib(3)=fib(2)+fib(1), but it doesn't need to recalculate fib(2), because we cached it.
This starts at the top of the tree and evaluate...
How does StartCoroutine / yield return pattern really work in Unity?
...
97
The first heading below is a straight answer to the question. The two headings after are more u...
内存管理内幕：动态分配的选择、折衷和实现 - C/C++ - 清泛网 - 专注C/C++及内核技术
...都获得了自己可以使用的地址空间，可以访问比您物理上安装的内存更多的内存。
在 32-位 x86 系统上，每一个进程可以访问 4 GB 内存。现在，大部分人的系统上并没有 4 GB 内存， 即使您将 swap 也算上， 每个进程所使用的内存...
Linux反编译全攻略 - 操作系统(内核) - 清泛网 - 专注C/C++及内核技术
... Ultimate Packer for eXecutables
Copyright (C) 1996, 1997, 1998, 1999, 2000, 2001, 2002, 2003, 2004
UPX 1.25 Markus F.X.J. Oberhumer & Laszlo Molnar Jun 29th 2004
File size Ratio Format Name
-------------------- ------ --------...
Awk学习笔记 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...分别是Alfred Aho、Brian Kernighan、Peter Weinberger。gawk是awk的GNU版本，它提供了Bell实验室和GNU的一些扩展。下面介绍的awk是以GUN的gawk为例的，在linux系统中已把awk链接到gawk，所以下面全部以awk进行介绍。
2. awk命令格式和选项
...
Repeat String - Javascript
...ans by a performance factor of 3x for simple one-character strings, and 8x-97x for short strings repeated more times, to 300x for repeating sentences, and infinitely wrong when taking the limit of the ratios of complexity of the algorithms as n goes to infinity. Also, there is another answer on this...
Fastest way to iterate over all the chars in a String
...buff[i], 459k new[i], 780k field access. (chars/ms)
len = 8192: 397k charAt(i), 712k cbuff[i], 446k new[i], 772k field access. (chars/ms)
SERVER MODE:
len = 2: 86k charAt(i), 41k cbuff[i], 46k new[i], 80k field access. (chars/ms)
len = 4: 571k charAt(i)...
分布式系统的事务处理 - 大数据 & AI - 清泛网 - 专注C/C++及内核技术
...个Master都提供read-write服务。这个模型是Master-Slave的加强版，数据间同步一般是通过Master间的异步完成，所以是最终一致性。 Master-Master的好处是，一台Master挂了，别的Master可以正常做读写服务，他和Master-Slave一样，当数据没有被...
How do I achieve the theoretical maximum of 4 FLOPs per cycle?
...7796447300922722721));
r6 = _mm_mul_pd(r1,_mm_set1_pd(0.24253562503633297352));
r7 = _mm_mul_pd(r1,_mm_set1_pd(4.1231056256176605498));
r8 = _mm_add_pd(r0,_mm_set1_pd(0.37796447300922722721));
r9 = _mm_add_pd(r1,_mm_set1_pd(0.24253562503633297352));
rA = _mm_sub_pd(r0,_mm_set1_pd...