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java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare();
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How do i call a method in that Activity, which i am making a toast message in with this code?
– lxknvlk
Mar 22 '15 at 9:20
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list.clear() vs list = new ArrayList(); [duplicate]
... the array copy that occurs when size exceeds capacity on an .add(Object) call.
– Platinum Azure
Aug 5 '11 at 19:12
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Large, persistent DataFrame in pandas
...(here's a tedious one: you could transcribe the file row-by-row into a pre-allocated NumPy array or memory-mapped file--np.mmap), but it's one I'll be working on in the near future. Another solution is to read the file in smaller pieces (use iterator=True, chunksize=1000) then concatenate then with ...
Calling the base constructor in C#
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Modify your constructor to the following so that it calls the base class constructor properly:
public class MyExceptionClass : Exception
{
public MyExceptionClass(string message, string extrainfo) : base(message)
{
//other stuff here
}
}
Note that a const...
Type safety: Unchecked cast
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Well, first of all, you're wasting memory with the new HashMap creation call. Your second line completely disregards the reference to this created hashmap, making it then available to the garbage collector. So, don't do that, use:
private ...
How to add a custom HTTP header to every WCF call?
...lients that using this service must pass an identifier every time they're calling service methods (because that identifier is important for what the called method should do). I thought it is a good idea to somehow put this identifier to the WCF header information.
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Reset local repository branch to be just like remote repository HEAD
...ely just "origin" (the default). You can use "git remote" to get a list of all remote names. You can then use "git remote <name>" to see which branches push/pull with each other (e.g. if your "master" branch was cloned from "master" in the remote named "origin", then you'll get a line that say...
Short circuit Array.forEach like calling break
...terribly pretty. A traditional for loop might be more appropriate if you really need to break inside it.
Use Array#some
Instead, use Array#some:
[1, 2, 3].some(function(el) {
console.log(el);
return el === 2;
});
This works because some returns true as soon as any of the callba...
How to give border to any element using css without adding border-width to the whole width of elemen
... Noted: outline doesn't define sides, so this works only if all sides are styled.
– Screenack
Mar 25 '13 at 1:02
1
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How do you get the “object reference” of an object in java when toString() and hashCode() have been
...ith it (what you want to do makes a difference with what you will need to call).
hashCode, as defined in the JavaDocs, says:
As much as is reasonably practical, the hashCode method defined by class Object does return distinct integers for distinct objects. (This is typically implemented by con...