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Rounding float in Ruby
...er, I can only use .round which basically turns it into an int, meaning 2.34.round # => 2. Is there a simple effect way to do something like 2.3465 # => 2.35
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Pandas index column title or name
...0]:
Column 1
foo
Apples 1
Oranges 2
Puppies 3
Ducks 4
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Does assignment with a comma work?
Why does aaa = 1,2,3 work and set the value of aaa to 1 ?
4 Answers
4
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Apply a function to every row of a matrix or a data frame
Suppose I have a n by 2 matrix and a function that takes a 2-vector as one of its arguments. I would like to apply the function to each row of the matrix and get a n-vector. How to do this in R?
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Array to Hash Ruby
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a = ["item 1", "item 2", "item 3", "item 4"]
h = Hash[*a] # => { "item 1" => "item 2", "item 3" => "item 4" }
That's it. The * is called the splat operator.
One caveat per @Mike Lewis (in the comments): "Be very careful with this. Rub...
Eclipse RCP Plug-in开发自学教程（Eclipse3.6） - 文档下载 - 清泛网 - ...
...受益，也希望大家能有版本意识，转载时注明来自salever@126.com。
之前有一套基于Eclipse3.3版本的教程，也是本人整理，由于本人的疏忽，导致网络上的版本各不相同，但分享已久，无法改变，希望大家谅解并使用新版本的教程...
Simple regular expression for a decimal with a precision of 2
What is the regular expression for a decimal with a precision of 2?
17 Answers
17
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Format number to always show 2 decimal places
I would like to format my numbers to always display 2 decimal places, rounding where applicable.
30 Answers
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Get the cartesian product of a series of lists?
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itertools.product
Available from Python 2.6.
import itertools
somelists = [
[1, 2, 3],
['a', 'b'],
[4, 5]
]
for element in itertools.product(*somelists):
print(element)
Which is the same as,
for element in itertools.product([1, 2, 3], ['a', 'b'], ...