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Call a Server-side Method on a Resource in a RESTful Way
...ense if a JSON representation included this:
"barks": {
"previous": [x_1, x_2, ..., x_n],
"next": x_n,
"frequency": 10
}
Treat the cron job as an implementation detail that the server hides from the interface. That's the beauty of a generic interface. The client doesn't have to know w...
How to add item to the beginning of List?
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Use Insert method of List<T>:
List.Insert Method (Int32, T): Inserts an element into the List at the specified index.
var names = new List<string> { "John", "Anna", "Monica" };
names.Insert(0, "Micheal"); // Insert to the first element
...
Log all requests from the python-requests module
...print name into that module:
import logging
import http.client
httpclient_logger = logging.getLogger("http.client")
def httpclient_logging_patch(level=logging.DEBUG):
"""Enable HTTPConnection debug logging to the logging framework"""
def httpclient_log(*args):
httpclient_logger.l...
Equivalent of Math.Min & Math.Max for Dates?
...much!
– tfrascaroli
May 31 '17 at 6:32
This is a very elegant solution
– pberggreen
...
What is a predicate in c#? [duplicate]
...redicate?
– Elaine
Jan 21 '15 at 15:32
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show 2 more comments
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What's the best way to iterate an Android Cursor?
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Alex StylAlex Styl
3,07522 gold badges2323 silver badges4242 bronze badges
8
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How do I handle newlines in JSON?
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answered Sep 3 '08 at 16:32
BlaMBlaM
26.1k3030 gold badges8888 silver badges104104 bronze badges
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Difference between Python's Generators and Iterators
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iterator is a more general concept: any object whose class has a __next__ method (next in Python 2) and an __iter__ method that does return self.
Every generator is an iterator, but not vice versa. A generator is built by calling a function that has one or more yield expressions (yield st...
Dynamic LINQ OrderBy on IEnumerable / IQueryable
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32
The accepted answer may have been the correct answer in 2008 but currently this is the easiest, most correct answer now.
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How to find the kth largest element in an unsorted array of length n in O(n)?
... = n(n+1)/2 - floor(n/2)(floor(n/2)+1)/2
<= n2/2 - (n/4)2/2
= (15/32)n2
where we take advantage of n being "sufficiently large" to replace the ugly floor(n/2) factors with the much cleaner (and smaller) n/4. Now we can continue with
cn + 2 (1/n) ∑i=floor(n/2) to n ai,
<= cn + (2a/n...
