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Replace values in list using Python [duplicate]

...but it doesn't actually save time: items = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] for index, item in enumerate(items): if not (item % 2): items[index] = None Here are (Python 3.6.3) timings demonstrating the non-timesave: In [1]: %%timeit ...: items = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10...
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How to pass optional arguments to a method in C++?

...ng_else(); } you can call myfunc in both ways and both are valid myfunc(10); // Mode will be set to default 0 myfunc(10, 1); // Mode will be set to 1 share | improve this answer | ...
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...--> Note: These conditional comments are no longer supported from IE 10 onwards. share | improve this answer | follow | ...
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GoTo Next Iteration in For Loop in java

... answered Jun 22 '12 at 17:10 Jigar JoshiJigar Joshi 219k4141 gold badges370370 silver badges417417 bronze badges ...
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Detect the specific iPhone/iPod touch model [duplicate]

... answered Jul 29 '10 at 17:32 djromerodjromero 19.1k44 gold badges6767 silver badges6767 bronze badges ...
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How to check if anonymous object has a method?

... answered Jun 9 '10 at 15:48 Sean VieiraSean Vieira 134k2828 gold badges272272 silver badges265265 bronze badges ...
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Add st, nd, rd and th (ordinal) suffix to a number

...n '14) accomplishes this: function ordinal_suffix_of(i) { var j = i % 10, k = i % 100; if (j == 1 && k != 11) { return i + "st"; } if (j == 2 && k != 12) { return i + "nd"; } if (j == 3 && k != 13) { return i + "rd"; ...
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is_file or file_exists in PHP

... answered Apr 27 '09 at 10:00 hbwhbw 14.6k55 gold badges4646 silver badges5656 bronze badges ...
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Repeat Character N Times

...less you need to support older browsers, you can simply write: "a".repeat(10) Before repeat, we used this hack: Array(11).join("a") // create string with 10 a's: "aaaaaaaaaa" (Note that an array of length 11 gets you only 10 "a"s, since Array.join puts the argument between the array elements.)...
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How to check if all list items have the same value and return it, or return an “otherValue” if they

... | edited Dec 9 '10 at 15:49 answered Dec 8 '10 at 17:32 ...