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Validating with an XML schema in Python

... lxml is pure python or not? (does require compilation/installation or you can just include it with your python scripts) – sorin Jun 14 '10 at 14:08 ...
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How do I format a string using a dictionary in python-3.x?

...3). In many languages, it is known as splat operator. In JavaScript, it's called spread operator. In python, there is no particular name given to this operator. – abhisekp Apr 15 '17 at 12:01 ...
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Receive JSON POST with PHP

...ontents('php://input'), true); This will save you the hassle of changing all $_POST to something else and allow you to still make normal post requests if you wish to take this line out. share | im...
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How do I clone a job in Jenkins?

...ether it exists. The default tab on the front page of Jenkins should list all existing jobs, but maybe your predecessor deleted the tab. You can create a new tab listing all jobs from http://your-jenkins/newView. share ...
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Eclipse cannot load SWT libraries

... I get an Unsatisfied Link Error and it will not open. I have recently installed the java JDK and Android SDK, could this be the problem? I followed this tutorial . ...
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Calling method using JavaScript prototype

Is it possible to call the base method from a prototype method in JavaScript if it's been overridden? 14 Answers ...
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Proper way to handle multiple forms on one page in Django

...ta. Include some hidden inputs if your froms don't have unique fields with all possible values being not empty. – Denis Otkidach Oct 24 '09 at 16:39 14 ...
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How to delete duplicate lines in a file without sorting it in Unix?

... To save it in a file we can do this awk '!seen[$0]++' merge_all.txt > output.txt – Akash Kandpal Jul 19 '18 at 11:42 5 ...
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How can I check if my python object is a number? [duplicate]

In Java the numeric types all descend from Number so I would use 5 Answers 5 ...
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Pythonic way to check if a list is sorted or not

... Actually we are not giving the answer anijhaw is looking for. Here is the one liner: all(l[i] <= l[i+1] for i in xrange(len(l)-1)) For Python 3: all(l[i] <= l[i+1] for i in range(len(l)-1)) ...