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Python regex find all overlapping matches?
...head, so the matches are technically non-overlapping:
import re
s = "123456789123456789"
matches = re.finditer(r'(?=(\d{10}))',s)
results = [int(match.group(1)) for match in matches]
# results:
# [1234567891,
# 2345678912,
# 3456789123,
# 4567891234,
# 5678912345,
# 6789123456,
# 7891234567...
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AnthonyWJonesAnthonyWJones
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camhcamh
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Jeroen
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answered May 22 '12 at 10:16
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answered Jun 21 '12 at 5:26
marc_smarc_s
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Jason
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answered Mar 8 '12 at 5:28
Noah WitherspoonNoah Witherspoon
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