大约有 47,000 项符合查询结果（耗时：0.0545秒） [XML]
WAMP error: Forbidden You don't have permission to access /phpmyadmin/ on this server
...Override all
Order Deny,Allow
Deny from all
Allow from 127.0.0.1
</Directory>
Modern versions of Apache 2.2 and up will look for a IPv6 loopback instead of a IPv4 loopback (your localhost).
The real problem is that wamp is binding to an IPv6 address. The fix:
just add ...
Could not load file or assembly 'Newtonsoft.Json, Version=4.5.0.0, Culture=neutral, PublicKeyToken=3
...
240
In package manager console execute: Update-Package –reinstall Newtonsoft.Json.
UPDATE
I orig...
Building executable jar with maven?
...at the answer given in the question you mentioned is just wrong (UPDATE - 20101106: someone fixed it, this answer refers to the version preceding the edit) and this explains, at least partially, why you run into troubles.
It generates two jar files in logmanager/target: logmanager-0.1.0.jar, and l...
How do Python's any and all functions work?
...or example,
>>> multiples_of_6 = (not (i % 6) for i in range(1, 10))
>>> any(multiples_of_6)
True
>>> list(multiples_of_6)
[False, False, False]
Here, (not (i % 6) for i in range(1, 10)) is a generator expression which returns True if the current number within 1 and 9 i...
Fastest way to iterate over all the chars in a String
...se now Java will store strings as byte[] by default.
SECOND UPDATE: As of 2016-10-25, on my AMDx64 8core and source 1.8, there is no difference between using 'charAt' and field access. It appears that the jvm is sufficiently optimized to inline and streamline any 'string.charAt(n)' calls.
THIRD UPDA...
Difference between MEAN.js and MEAN.io
...response!
– CMPSoares
Apr 22 '14 at 0:08
7
...
Reordering arrays
... would be:
Array.prototype.move = function (from, to) {
this.splice(to, 0, this.splice(from, 1)[0]);
};
Then just use:
var ar = [1,2,3,4,5];
ar.move(0,3);
alert(ar) // 2,3,4,1,5
Diagram:
share
|
...
Java String - See if a string contains only numbers and not letters
...Z]+") == false && text.length() > 2){
to:
if (text.matches("[0-9]+") && text.length() > 2) {
Instead of checking that the string doesn't contain alphabetic characters, check to be sure it contains only numerics.
If you actually want to use the numeric value, use Integer.p...
How to track down a “double free or corruption” error
...
answered May 25 '10 at 8:42
HasturkunHasturkun
31.2k55 gold badges6565 silver badges9595 bronze badges
...