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Bomb dropping algorithm
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There is a way to reduce this to a simple sub-problem.
There are 2 parts to the explanation, the algorithm, and the reason the algorithm
provides an optimal solution. The first won't make sense without the second, so I'll
start with the why.
If you think of bombin...
How do I get a file extension in PHP?
This is a question you can read everywhere on the web with various answers:
28 Answers
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What is a method that can be used to increment letters?
Does anyone know of a Javascript library (e.g. underscore, jQuery, MooTools, etc.) that offers a method of incrementing a letter?
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Is a `=default` move constructor equivalent to a member-wise move constructor?
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Yes both are the same.
But
struct Example {
int a, b;
Example(int mA, int mB) : a{mA}, b{mB} { }
Example(const Example& mE) = default;
Example(Example&& mE) = default;
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Convert all first letter to upper case, rest lower for each word
I have a string of text (about 5-6 words mostly) that I need to convert.
11 Answers
11...
Get next / previous element using JavaScript?
...ave to collate them inside a collection.
var divs = document.getElementsByTagName("div");
//divs now contain each and every div element on the page
var selectionDiv = document.getElementById("MySecondDiv");
So basically with selectionDiv iterate through the collection to find its index, and the...
Current time formatting with Javascript
...rts:
getFullYear() - Returns the 4-digit year
getMonth() - Returns a zero-based integer (0-11) representing the month of the year.
getDate() - Returns the day of the month (1-31).
getDay() - Returns the day of the week (0-6). 0 is Sunday, 6 is Saturday.
getHours() - Returns the hour of the day (0-...
Volatile Vs Atomic [duplicate]
I read somewhere below line.
6 Answers
6
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Two single-column indexes vs one two-column index in MySQL?
I'm faced with the following and I'm not sure what's best practice.
4 Answers
4
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Replace non-ASCII characters with a single space
... if ord(i) < 128 else ' ' for i in text])
This handles characters one by one and would still use one space per character replaced.
Your regular expression should just replace consecutive non-ASCII characters with a space:
re.sub(r'[^\x00-\x7F]+',' ', text)
Note the + there.
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