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Can I get the name of the currently running function in JavaScript?
...t information.
In older versions of JS you can get it by using arguments.callee.
You may have to parse out the name though, as it will probably include some extra junk. Though, in some implementations you can simply get the name using arguments.callee.name.
Parsing:
function DisplayMyName()
{
...
Mixing a PHP variable with a string literal
...ossible to inline function calls with such a method? Something similar to "foo{implode(',', [abc])}bar"
– velop
Apr 27 '17 at 15:46
...
How to Test Facebook Connect Locally
...which is ( http://localhost:xxxx/test.aspx )
So how I can test Facebook locally (i.e How I can change the callback url) ?
1...
Best exception for an invalid generic type argument
...ere's a way in which NotSupportedException is obviously good enough, especially given its common-sense meaning. Having said that, I'm not sure if it's just right.
Given the purpose of Unconstrained Melody ...
There are various useful things that can be done with generic
methods/classes where ...
Populating a ListView using an ArrayList?
... @ Amokrane Chentir: I think that the "setContentView" method must be called before "findViewById" or else no ListView will be found.
– Petru
Jun 26 '12 at 20:36
...
The new keyword “auto”; When should it be used to declare a variable type? [duplicate]
... v.end(); ++it) //v is some [std] container
{
//..
}
Or, more generally,
//good : auto increases readability here
for(auto it = std::begin(v); it != std::end(v); ++it)//v could be array as well
{
//..
}
But when the type is not very well-known and infrequently used , then I think ...
Coding in Other (Spoken) Languages
...
If I understood well the question actually is: "does every single coder in the world know enough English to use the exact same reserved words as I do?"
Well.. English is not the subject here but programming language reserved words. I mean, when I started about ...
What can I use instead of the arrow operator, `->`?
...
I mostly read it right-to-left and call "in"
foo->bar->baz = qux->croak
becomes:
"baz in bar in foo becomes croak in qux."
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Default value to a parameter while passing by reference in C++
...efault any argument you wish:
class A {};
class B {};
class C {};
void foo (A const &, B const &, C const &);
void foo (B const &, C const &); // A defaulted
void foo (A const &, C const &); // B defaulted
void foo (C const &); // A & B defaulted etc...
It i...
What does the unary plus operator do?
...
It's there to be overloaded if you feel the need; for all predefined types it's essentially a no-op.
The practical uses of a no-op unary arithmetic operator are pretty limited, and tend to relate to the consequences of using a value in an arithmetic expression, rather than the ...