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What is the best way to check for Internet connectivity using .NET?
...g host = "google.com";
byte[] buffer = new byte[32];
int timeout = 1000;
PingOptions pingOptions = new PingOptions();
PingReply reply = myPing.Send(host, timeout, buffer, pingOptions);
return (reply.Status == IPStatus.Success);
}
catch (Exception) {
return false;
}
...
How to find foreign key dependencies in SQL Server?
...
100
try: sp_help [table_name]
you will get all information about table, including all foreign key...
PHPUnit assert that an exception was thrown?
...n
};
$this->assertException( $test, 'InvalidArgumentException', 100, 'expected message' );
}
I also made a trait for lovers of nice code..
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iOS JavaScript bridge
... }
}
Now inside of your javascript you can call:
yourBridge.someEvent(100, "hello");
yourBridge.testfoo();
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十年磨一“饼” 一个70后连续创业者的心路历程 - 资讯 - 清泛网 - 专注C/C+...
...下直营店铺的重模式，在经历三年多的时间，公司亏损了100万美金后遗憾偃旗息鼓。此后的几年，我有一直关注传统行业和互联网行业的发展动向。
记得“李开复”老师曾经有一句创业箴言：选择创业项目，要在熟悉的和时下...
Is it possible to Pivot data using LINQ?
... {
IEnumerable<CustData> myList = GetCustData().Take(100);
var query = myList
.GroupBy(c => c.CustId)
.Select(g =>
{
CustomerStatistics results = g.Aggregate(new CustomerStatistics(), (result...
Check whether an array is a subset of another
... the solutions, and the results are drastic. These two solutions are about 100x faster than the .Except() and .Intersect() solutions, and use no additional memory.
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How to convert enum value to int?
...de clarity), a data type that is DB friendly, and I don't have to research 100 enum alternatives to do it the "android way". Simple and effective.
– John Ward
Mar 1 '17 at 15:08
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Remove all occurrences of a value from a list?
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Consider x = [1] * 10000 + [2] * 1000. The loop body executes 1000 times and .remove() has to skip 10000 elements every time it's invoked. That smells like O(n*n) to me but is no proof. I think the proof would be to assume that the number of 2s...
How to generate a random string in Ruby
...he most upvotes:
require 'benchmark'
require 'securerandom'
len = 10
n = 100_000
Benchmark.bm(12) do |x|
x.report('SecureRandom') { n.times { SecureRandom.alphanumeric(len) } }
x.report('rand') do
o = [('a'..'z'), ('A'..'Z'), (0..9)].map(&:to_a).flatten
n.times { (0...len).map { o...