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Unicode character as bullet for list-item in CSS
...n will have to use the li:before solution.
– CoderGuy123
Sep 8 '16 at 11:03
1
Works. Welcome to t...
Where do I find the definition of size_t?
...
123
From Wikipedia
The stdlib.h and stddef.h header files define a datatype called size_t1 which ...
App Inventor 2 数学代码块 · App Inventor 2 中文网
... 隐私策略和使用条款 技术支持 service@fun123.cn
What is your single most favorite command-line trick using Bash? [closed]
...p to see all of your keyboard shortcuts listed? There are over 455 on Mac OS X by default.
105 Answers
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How to add leading zeros?
...paste0) are often the first string manipulation functions that you come across. They aren't really designed for manipulating numbers, but they can be used for that. In the simple case where we always have to prepend a single zero, paste0 is the best solution.
paste0("0", anim)
## [1] "025499" "02...
How do you beta test an iphone app?
...uch better solution than anything else out there.
– Josh Brown
Feb 2 '11 at 6:16
This one is about 10x prettier than "...
How can I remove the first line of a text file using bash/sed script?
...han sed. tail is also available on BSD and the -n +2 flag is consistent across both tools. Check the FreeBSD or OS X man pages for more.
The BSD version can be much slower than sed, though. I wonder how they managed that; tail should just read a file line by line while sed does pretty complex oper...
Haskell: Converting Int to String
...an Int, use:
module Lib
( someFunc
) where
someFunc :: IO ()
x = 123
someFunc = putStrLn (show x)
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How to change the type of a field?
...now how you'd convert a string (think currency like '1.23') to the integer 123? I assume you'd have to parse it as a float or decimal, multiply it by 100, then save it as an integer, but I can't find the right docs to do this. Thanks!
– Brian Armstrong
Feb 23...
Test if string is a number in Ruby on Rails
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\Z allows to have \n at the end of the string, so "123\n" will pass validation, regardless that it's not fully numeric. But if you use \z then it will be more correct regexp: /\A\d+\z/
– SunnyMagadan
Aug 14 '17 at 9:14
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