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Why in Java 8 split sometimes removes empty strings at start of result array?
... post a fragment of code from the JDK? Remember the copyright problem with Google - Harry Potter - Oracle?
– Paul Vargas
Mar 28 '14 at 17:24
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How to optimize for-comprehensions and loops in Scala?
...m is working on improving for performance in simple cases:
http://groups.google.com/group/scala-user/browse_thread/thread/86adb44d72ef4498
http://groups.google.com/group/scala-language/browse_thread/thread/94740a10205dddd2
Here is the issue in the bug tracker:
https://issues.scala-lang.org/brows...
C# delete a folder and all files and folders within that folder
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Why read the manual when it's much quicker to google it and end up here?
– reggaeguitar
Jan 23 '15 at 21:08
5
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Charts for Android [closed]
...chart. But the problem is, there is no library for that charts. I have got Google chart API for candlestick chart. But I don't want graph/chart in a webview.
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Check cell for a specific letter or set of letters
In a Google Spreadsheet, I want to use a formula that will output a certain text or number if a certain cell contains certain letters.
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OAuth那些事儿 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...设我们做了一个SNS，它有一个功能，可以让会员把他们在Google上的联系人导入到SNS上，那么此时的消费方就是SNS，而服务提供者则是Google。
注：Google APIs支持OAuth。
消费方如果想使用服务提供者的OAuth功能，通常需要先申请两...
App Inventor 2 语音交互机器人Robot，使用讯飞语音识别引擎 - App Invento...
...开始学习"。
1、语音识别器
一般Android手机提供的是Google语音识别引擎，但是经过测试，中文支持不好，经常识别失败，因此这里改用讯飞语音+识别引擎来进行，体验较好，识别率很高。
不过目前版本还稳定维持在1.1.1045...
安卓(Android) 、鸿蒙(HarmonyOS) 、苹果(iOS) 测试方式及App上架方式对比 ...
...维度安卓 (Android)鸿蒙 (HarmonyOS NEXT)苹果 (iOS)主要应用商店Google Play / 各大国内应用商店华为应用市场 (AppGallery)App Store开发者注册费用$25 一次性（Google Play）
国内商店大多免费免费99美元/年（约680元/年）应用包格式.apk / .aab.hap / ...
Why does the JVM still not support tail-call optimization?
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The link to the cited article is now broken, though Google does have it cached. More importantly, the author's reasoning is faulty. The example given could be tail-call optimized, using static and not just dynamic compilation, if only the compiler inserted an instanceof check ...
Get protocol + host name from URL
...think your url is valid then this will work all the time
domain = "http://google.com".split("://")[1].split("/")[0]
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