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Bytes of a string in Java
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291
A string is a list of characters (i.e. code points). The number of bytes taken to represent t...
ImportError: No module named pip
OS: Mac OS X 10.7.5
Python Ver: 2.7.5
16 Answers
16
...
How to find the operating system version using JavaScript?
...onsole.log(navigator);
You'll see something like this
# platform = Win32
# appCodeName = Mozilla
# appName = Netscape
# appVersion = 5.0 (Windows; en-US)
# language = en-US
# mimeTypes = [object MimeTypeArray]
# oscpu = Windows NT 5.1
# vendor = Firefox
# vendorSub = 1.0.7
# product = Gecko
# pr...
What does `kill -0 $pid` in a shell script do?
... then no signal is sent, but error checking is still performed.
...
kill(2)
$ man 2 kill
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If sig is 0, then no signal is sent, but error checking is still performed; this
can be used to check for the existence of a process ID or process group ID.
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multiprocessing: How do I share a dict among multiple processes?
... multiprocessing import Process, Manager
def f(d):
d[1] += '1'
d['2'] += 2
if __name__ == '__main__':
manager = Manager()
d = manager.dict()
d[1] = '1'
d['2'] = 2
p1 = Process(target=f, args=(d,))
p2 = Process(target=f, args=(d,))
p1.start()
p2.start()
...
Lazy Method for Reading Big File in Python?
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12 Answers
12
Active
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Get the key corresponding to the minimum value within a dictionary
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622
Best: min(d, key=d.get) -- no reason to interpose a useless lambda indirection layer or extract...
SQL DELETE with INNER JOIN
There are 2 tables, spawnlist and npc , and I need to delete data from spawnlsit .
npc_templateid = n.idTemplate is the only thing that "connect" the tables.
I have tried this script but it doesn't work.
...
When should I use nil and NULL in Objective-C?
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edited Jan 27 '16 at 14:15
community wiki
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Maximum number of characters using keystrokes A, Ctrl+A, Ctrl+C and Ctrl+V
... O(N), but since the numbers grow at an exponential rate it is actually O(N2) due to the complexity of multiplying the large numbers. Below is a Python implementation. It takes about 0.5 seconds to calculate for N=50,000.
def max_chars(n):
dp = [0] * (n+1)
for i in xrange(n):
dp[i+1] = max(...