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Working with huge files in VIM
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Edit SMALLPART using your favourite editor.
Combine the file:
(head -n 3 HUGEFILE; cat SMALLPART; sed -e '1,5d' HUGEFILE) > HUGEFILE.new
i.e: pick all the lines before the edited lines from the HUGEFILE (which in this case is the top 3 lines), combine it with the edited lines (in this cas...
Pythonic way to print list items
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Assuming you are using Python 3.x:
print(*myList, sep='\n')
You can get the same behavior on Python 2.x using from __future__ import print_function, as noted by mgilson in comments.
With the print statement on Python 2.x you will need iteration of som...
What does a b prefix before a python string mean?
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63
This is Python3 bytes literal. This prefix is absent in Python 2.5 and older (it is equivalent t...
Overriding id on create in ActiveRecord
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13 Answers
13
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Find and replace string values in list
... a float/integer?
– Patriots299
Dec 31 '18 at 20:38
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Multiple Type Constraints in Swift
...e T:SomeProtocol, T:SomeOtherProtocol>(arg: T) {
// stuff
}
Swift 3 & 4:
func someFunc<T: SomeProtocol & SomeOtherProtocol>(arg: T) {
// stuff
}
or the more powerful where clause:
func someFunc<T>(arg: T) where T:SomeProtocol, T:SomeOtherProtocol{
// stuff
}
...
Remove duplicated rows using dplyr
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139
Note: dplyr now contains the distinct function for this purpose.
Original answer below:
lib...
In git, is there a way to show untracked stashed files without applying the stash?
...ut is pretty obvious from The commit which introduced the -u feature, 787513..., and the way the rest of the documentation for git-stash phrases things... or just by doing git log --graph stash@{0})
You can view just the "untracked" portion of the stash via:
git show stash@{0}^3
or, just the "un...
Sort hash by key, return hash in Ruby
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answered Mar 11 '14 at 2:03
Mark ThomasMark Thomas
34.8k99 gold badges6666 silver badges9797 bronze badges
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Numpy first occurrence of value greater than existing value
...nce are returned.") and doesn't save another list.
In [2]: N = 10000
In [3]: aa = np.arange(-N,N)
In [4]: timeit np.argmax(aa>N/2)
100000 loops, best of 3: 52.3 us per loop
In [5]: timeit np.where(aa>N/2)[0][0]
10000 loops, best of 3: 141 us per loop
In [6]: timeit np.nonzero(aa>N/2)[0...