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Get exit code of a background process
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Thanks! This one seems to me the simplest approach.
– Luke Davis
Sep 26 '17 at 20:20
4
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The breakpoint will not currently be hit. No symbols have been loaded for this document in a Silverl
...as u tell.. some of them are class library projects.. follwing error popup appears: "A project with an Output Type of Class Library cannot be started directly"
– Muhammad Azeem
Oct 19 '12 at 10:31
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Run php script as daemon process
...me other alternatives suitable for my case. Any information will be really appreciated.
14 Answers
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Android notification is not showing
...onCompat.Builder mBuilder =
new NotificationCompat.Builder(mContext.getApplicationContext(), "notify_001");
Intent ii = new Intent(mContext.getApplicationContext(), RootActivity.class);
PendingIntent pendingIntent = PendingIntent.getActivity(mContext, 0, ii, 0);
NotificationCompat.BigTextStyle ...
How to manage startActivityForResult on Android?
...ctivityResult() then check its parameters:
requestCode identifies which app returned these results. This is defined by you when you call startActivityForResult().
resultCode informs you whether this app succeeded, failed, or something different
data holds any information returned by this app. Thi...
django test app error - Got an error creating the test database: permission denied to create databas
When I try to test any app with command (I noticed it when I tried to deploy myproject using fabric, which uses this command):
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Using node.js as a simple web server
...p-server -g
Now you can run a server via the following commands:
$ cd MyApp
$ http-server
If you're using NPM 5.2.0 or newer, you can use http-server without installing it with npx. This isn't recommended for use in production but is a great way to quickly get a server running on localhost.
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IIS - 401.3 - Unauthorized
...rying to get started with using IIS. I created a new site on IIS Manager, mapped it to a folder on my file system and added index.html to the folder. I have set the port to 85 for this site. When I try to access http://localhost:85/index.html , I get the following error message:
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Flask-SQLalchemy update a row's information
...ask
from flask.ext.sqlalchemy import SQLAlchemy
from pprint import pprint
app = Flask(__name__)
app.config['SQLALCHEMY_DATABASE_URI'] = 'sqllite:////tmp/users.db'
db = SQLAlchemy(app)
class User(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(80), unique...
Best practice using NSLocalizedString
I'm (like all others) using NSLocalizedString to localize my app.
9 Answers
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