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What's the fastest way to loop through an array in JavaScript?
I learned from books that you should write for loop like this:
22 Answers
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How to create the most compact mapping n → isprime(n) up to a limit N?
Naturally, for bool isprime(number) there would be a data structure I could query.
I define the best algorithm , to be the algorithm that produces a data structure with lowest memory consumption for the range (1, N], where N is a constant.
Just an example of what I am looking for: I could rep...
Detect if value is number in MySQL
Is there a way to detect if a value is a number in a MySQL query? Such as
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Is there a better way of writing v = (v == 0 ? 1 : 0); [closed]
I want to toggle a variable between 0 and 1. If it's 0 I want to set it to 1, else if it's 1 I want to set it to 0.
31 Answ...
Apply a function to every row of a matrix or a data frame
Suppose I have a n by 2 matrix and a function that takes a 2-vector as one of its arguments. I would like to apply the function to each row of the matrix and get a n-vector. How to do this in R?
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A weighted version of random.choice
I needed to write a weighted version of random.choice (each element in the list has a different probability for being selected). This is what I came up with:
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How do you round a number to two decimal places in C#?
I want to do this using the Math.Round function
15 Answers
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How do you check whether a number is divisible by another number (Python)?
I need to test whether each number from 1 to 1000 is a multiple of 3 or a multiple of 5. The way I thought I'd do this would be to divide the number by 3, and if the result is an integer then it would be a multiple of 3. Same with 5.
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In Python, how do I convert all of the items in a list to floats?
I have a script which reads a text file, pulls decimal numbers out of it as strings and places them into a list.
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Email Address Validation in Android on EditText [duplicate]
How can we perform Email Validation on edittext in android ? I have gone through google & SO but I didn't find out a simple way to validate it.
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