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How do you cast a List of supertypes to a List of subtypes?
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Simply casting to List<TestB> almost works; but it doesn't work because you can't cast a generic type of one parameter to another. However, you can cast through an intermediate wildcard type and it will be allowed (since you can cast to and from wil...
Unicode equivalents for \w and \b in Java regular expressions?
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Source code
The source code for the rewriting functions I discuss below is available here.
Update in Java 7
Sun’s updated Pattern class for JDK7 has a marvelous new flag, UNICODE_CHARACTER_CLASS, which makes everything work right again. It’s available as an embeddable (?U) for inside ...
How to use OR condition in a JavaScript IF statement?
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Simply use the logical "OR" operator, that is ||.
if (A || B)
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Javascript reduce on array of objects
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After the first iteration your're returning a number and then trying to get property x of it to add to the next object which is undefined and maths involving undefined results in NaN.
try returning an object contain an x property with the sum of the x properties of the pa...
What's this =! operator? [duplicate]
I was surprised by this code:
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How do I convert Long to byte[] and back in java
How do I convert a long to a byte[] and back in Java?
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In C++, what is a virtual base class?
I want to know what a " virtual base class " is and what it means.
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Integer division with remainder in JavaScript?
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For some number y and some divisor x compute the quotient (quotient) and remainder (remainder) as:
var quotient = Math.floor(y/x);
var remainder = y % x;
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What is the most efficient way to loop through dataframes with pandas? [duplicate]
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The newest versions of pandas now include a built-in function for iterating over rows.
for index, row in df.iterrows():
# do some logic here
Or, if you want it faster use itertuples()
But, unutbu's suggestion to use numpy functions to avoid iterating over row...
Determine if 2 lists have the same elements, regardless of order? [duplicate]
Sorry for the simple question, but I'm having a hard time finding the answer.
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