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Makefile经典教程（入门必备） - C/C++ - 清泛网 - 专注C++内核技术
...因为我基本上都是在Unix下使用make，以前在SCO Unix和IBM的AIX，现在在Linux、Solaris、HP-UX、AIX和Alpha下使用，Linux和Solaris下更多一点。不过，我可以肯定的是，在Unix下的make，无论是哪种平台，几乎都使用了Richard Stallman开发的make和cc/...
Makefile经典教程（入门必备） - C/C++ - 清泛网 - 专注C++内核技术
...因为我基本上都是在Unix下使用make，以前在SCO Unix和IBM的AIX，现在在Linux、Solaris、HP-UX、AIX和Alpha下使用，Linux和Solaris下更多一点。不过，我可以肯定的是，在Unix下的make，无论是哪种平台，几乎都使用了Richard Stallman开发的make和cc/...
Makefile经典教程（入门必备） - C/C++ - 清泛网 - 专注C++内核技术
...因为我基本上都是在Unix下使用make，以前在SCO Unix和IBM的AIX，现在在Linux、Solaris、HP-UX、AIX和Alpha下使用，Linux和Solaris下更多一点。不过，我可以肯定的是，在Unix下的make，无论是哪种平台，几乎都使用了Richard Stallman开发的make和cc/...
Makefile经典教程（入门必备） - C/C++ - 清泛网 - 专注C++内核技术
...因为我基本上都是在Unix下使用make，以前在SCO Unix和IBM的AIX，现在在Linux、Solaris、HP-UX、AIX和Alpha下使用，Linux和Solaris下更多一点。不过，我可以肯定的是，在Unix下的make，无论是哪种平台，几乎都使用了Richard Stallman开发的make和cc/...
Guid.NewGuid() vs. new Guid()
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I'll add this for fun. For a 1% chance of collision, you'd need to generate about 2,600,000,000,000,000,000 GUIDs
– Clinton Ward
Aug 13 '12 at 16:20
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Haskell: Converting Int to String
...an Int, use:
module Lib
( someFunc
) where
someFunc :: IO ()
x = 123
someFunc = putStrLn (show x)
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How to change the type of a field?
...now how you'd convert a string (think currency like '1.23') to the integer 123? I assume you'd have to parse it as a float or decimal, multiply it by 100, then save it as an integer, but I can't find the right docs to do this. Thanks!
– Brian Armstrong
Feb 23...
Best way to store time (hh:mm) in a database
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Another fun problem is if you are relying on the time component, it will not account for the Daylight savings adjustments when used at different times of the year.
– Chris Seufert
Nov 23 '17 at ...
Get an object properties list in Objective-C
...}
free(properties);
}
This required me to make a 'getPropertyType' C function, which is mainly taken from an Apple code sample (can't remember right now the exact source):
static const char *getPropertyType(objc_property_t property) {
const char *attributes = property_getAttributes(proper...
Test if string is a number in Ruby on Rails
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\Z allows to have \n at the end of the string, so "123\n" will pass validation, regardless that it's not fully numeric. But if you use \z then it will be more correct regexp: /\A\d+\z/
– SunnyMagadan
Aug 14 '17 at 9:14
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