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How to get the type of a variable in MATLAB?

... answered Feb 23 '09 at 17:36 Daniel LeCheminantDaniel LeCheminant 47.3k1515 gold badges115115 silver badges113113 bronze badges ...
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How do I get a list of all the duplicate items using pandas in python?

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How to cancel a Task in await?

... Read up on Cancellation (which was introduced in .NET 4.0 and is largely unchanged since then) and the Task-Based Asynchronous Pattern, which provides guidelines on how to use CancellationToken with async methods. To summarize, you pass a CancellationToken into each method that s...
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Are SVG parameters such as 'xmlns' and 'version' needed?

... sleske 70.7k3030 gold badges157157 silver badges209209 bronze badges answered Aug 27 '13 at 14:32 Robert Long...
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Shorten string without cutting words in JavaScript

...the string to the maximum length var trimmedString = yourString.substr(0, maxLength); //re-trim if we are in the middle of a word and trimmedString = trimmedString.substr(0, Math.min(trimmedString.length, trimmedString.lastIndexOf(" "))) } ...
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Drawing an image from a data URL to a canvas

...t('2d'); var img = new Image; img.onload = function(){ ctx.drawImage(img,0,0); // Or at whatever offset you like }; img.src = strDataURI; Edit: I previously suggested in this space that it might not be necessary to use the onload handler when a data URI is involved. Based on experimental tests f...
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Set scroll position

... You can use window.scrollTo(), like this: window.scrollTo(0, 0); // values are x,y-offset share | improve this answer | follow | ...
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Why does Go have a “goto” statement

...mple, in the math/gamma.go file, the goto statement is used: for x < 0 { if x > -1e-09 { goto small } z = z / x x = x + 1 } for x < 2 { if x < 1e-09 { goto small } z = z / x x = x + 1 } if x == 2 { return z } x = x - 2 p ...
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What would cause an algorithm to have O(log log n) complexity?

... 220 O(log log n) terms can show up in a variety of different places, but there are typically two mai...
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Check whether a string contains a substring

...| edited Dec 15 '15 at 9:40 answered Sep 2 '11 at 12:21 Eug...