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Is there a bash command which counts files?
Is there a bash command which counts the number of files that match a pattern?
14 Answers
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How to convert an image to base64 encoding?
...yfolder/myimage.png';
$type = pathinfo($path, PATHINFO_EXTENSION);
$data = file_get_contents($path);
$base64 = 'data:image/' . $type . ';base64,' . base64_encode($data);
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Mac zip compress without __MACOSX folder?
When I compress files with the built in zip compressor in Mac OSX, it results in an extra folder titled "__MACOSX" created in the extracted zip.
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Can I 'git commit' a file and ignore its content changes?
...ir own local configuration. That configuration information is stored in a file called devtargets.rb which is used in our rake build tasks. I don't want developers to clobber each other's devtargets file, though.
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How to force the browser to reload cached CSS/JS files?
...fox and Opera) are very zealous in using cached copies of .css and .js files, even between browser sessions. This leads to a problem when you update one of these files but the user's browser keeps on using the cached copy.
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Using R to download zipped data file, extract, and import data
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Zip archives are actually more a 'filesystem' with content metadata etc. See help(unzip) for details. So to do what you sketch out above you need to
Create a temp. file name (eg tempfile())
Use download.file() to fetch the file into the temp. file
Use unz...
FileSystemWatcher vs polling to watch for file changes
I need to setup an application that watches for files being created in a directory, both locally or on a network drive.
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How to git-cherry-pick only changes to certain files?
If I want to merge into a Git branch the changes made only to some of the files changed in a particular commit which includes changes to multiple files, how can this be achieved?
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node.js require all files in a folder?
How do I require all files in a folder in node.js?
14 Answers
14
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JavaScript: Upload file
...tionally with await-try-catch
let photo = document.getElementById("image-file").files[0];
let formData = new FormData();
formData.append("photo", photo);
fetch('/upload/image', {method: "POST", body: formData});
async function SavePhoto(inp)
{
let user = { name:'john', age:34 };
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