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Efficient way to determine number of digits in an integer
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107
Well, the most efficient way, presuming you know the size of the integer, would be a lookup. S...
Grep characters before and after match?
... characters after
$> echo "some123_string_and_another" | grep -o -P '.{0,3}string.{0,4}'
23_string_and
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How to determine CPU and memory consumption from inside a process?
... now;
lastUserCPU = user;
lastSysCPU = sys;
return percent * 100;
}
Linux
On Linux the choice that seemed obvious at first was to use the POSIX APIs like getrusage() etc. I spent some time trying to get this to work, but never got meaningful values. When I finally checked the kern...
Auto-center map with multiple markers in Google Maps API v3
...tLngBounds();
var infowindow = new google.maps.InfoWindow();
for (i = 0; i < locations.length; i++) {
var marker = new google.maps.Marker({
position: new google.maps.LatLng(locations[i][1], locations[i][2]),
map: map
});
//extend the bounds to include each marker's position
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Generate array of all letters and digits
...g ruby, is it possible to make an array of each letter in the alphabet and 0-9 easily?
7 Answers
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Odd behavior when Java converts int to byte?
...mber is the positive version of that number
For example: 11111111 goes to 00000001 = -1. This is what Java will display as the value.
What you probably want to do is know the unsigned value of the byte.
You can accomplish this with a bitmask that deletes everything but the least significant 8 bit...
How do you convert epoch time in C#?
...ou convert Unix epoch time into real time in C#? (Epoch beginning 1/1/1970)
14 Answers
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Why does ('0' ? 'a' : 'b') behave different than ('0' == true ? 'a' : 'b') [duplicate]
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208
+500
First, ...
Multiple aggregations of the same column using pandas GroupBy.agg()
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You can simply pass the functions as a list:
In [20]: df.groupby("dummy").agg({"returns": [np.mean, np.sum]})
Out[20]:
mean sum
dummy
1 0.036901 0.369012
or as a dictionary:
In [21]: df.groupby('dummy').agg({'returns':
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Angular.js ng-repeat across multiple tr's
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edited May 23 '17 at 12:10
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answered Oct 19 '12 at 20:19
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