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Regular expression to extract text between square brackets
...rs needs to be told explicitly to apply the regex repeatedly (for example, by using the /g flag in JavaScript).
– Tim Pietzcker
Dec 8 '17 at 15:30
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How do I convert a PDF document to a preview image in PHP? [closed]
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smart answer. not given by other but you notice and wrote.
– Ashu Kumar
Aug 20 '18 at 11:50
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jquery, domain, get URL
... I would actually recommend using window.location.host (as bibby posted). I just fixed a bug where document.domain was being set to the root domain instead of the subdomain.
– Derek Morrison
Mar 15 '13 at 20:03
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how to check if a form is valid programmatically using jQuery Validation Plugin
...w if there is any way I can check if the form is considered in valid state by jquery validation plugin from anywhere in my javascript code.
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How to merge every two lines into one from the command line?
...ch separates on words rather than lines. -d can be used to split the input by any single character.
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Microsoft Web API: How do you do a Server.MapPath?
... Its giving the controller path, so can I get the service path by using the "HostingEnvironment"?
– Md Aslam
Dec 11 '18 at 9:20
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Alter a MySQL column to be AUTO_INCREMENT
...st nothing) for MySQL integer types. The only thing that may be influenced by the number is the display width, and it is up to the client to do that. But don't be deceived and think that it works like it does for VARCHAR and DECIMAL types - in those cases, the amount of data you can store in there i...
How do I create a new line in Javascript?
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By definition, if the OP is using document.write, it's an HTML page, not an XHTML page. <br> is the correct linebreak for an HTML page. <br /> is XHTML.
– T.J. Crowder
Apr 22...
Remove an item from array using UnderscoreJS
...lain JavaScript, this has been answered already: remove objects from array by object property.
Using underscore.js, you could combine .findWhere with .without:
var arr = [{
id: 1,
name: 'a'
}, {
id: 2,
name: 'b'
}, {
id: 3,
name: 'c'
}];
//substract third
arr = _.witho...
Bundler: Command not found
I am hosting on a vps, ubuntu 10.04, rails 3, ruby and mysql installed correctly by following some tutorials. If I run bundle check or bundle install I get the error '-bash: bundle: command not found'. From gem list --local I see 'bundler (1.0.2, 1.0.0)' is installed.
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