大约有 43,000 项符合查询结果（耗时：0.0290秒） [XML]
SQL WHERE ID IN (id1, id2, …, idn)
...izes like below:
Divide you list of Ids into chunks of fixed number, say 100
Chunk size should be decided based upon the memory size of your server
Suppose you have 10000 Ids, you will have 10000/100 = 100 chunks
Process one chunk at a time resulting in 100 database calls for select
Why should y...
Matplotlib plots: removing axis, legends and white spaces
...corner at the point located at (0 %, 0 %), and with a width and height of (100 %, 100 %).
– PhilMacKay
Jul 22 '13 at 19:40
...
Push git commits & tags simultaneously
... also push just one tag with your current branch commit:
git push origin : v1.0.0
You can combine the --tags option with a refspec like:
git push origin --tags :
(since --tags means: All refs under refs/tags are pushed, in addition to refspecs explicitly listed on the command line)
You also have...
Why would you use an ivar?
...
100
Encapsulation
If the ivar is private, the other parts of the program can't get at it as easily...
SVG: text inside rect
...p://www.w3.org/2000/svg">
<g>
<rect x="0" y="0" width="100" height="100" fill="red"></rect>
<text x="0" y="50" font-family="Verdana" font-size="35" fill="blue">Hello</text>
</g>
</svg>
...
Sleeping in a batch file
...Waiting 15 seconds
PING 1.1.1.1 -n 1 -w 15000 > NUL
or
PING -n 15 -w 1000 127.1 >NUL
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if else in a list comprehension [duplicate]
...
user225312user225312
100k6060 gold badges158158 silver badges179179 bronze badges
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simulate background-size:cover on or
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+100
This is something I pulled my hair out over for a while, but I came across a great solution that doesn't use any script, and can ach...
ActiveRecord.find(array_of_ids), preserving order
...ql called FIELD()
Here is how you could use it in .find():
>> ids = [100, 1, 6]
=> [100, 1, 6]
>> WordDocument.find(ids).collect(&:id)
=> [1, 6, 100]
>> WordDocument.find(ids, :order => "field(id, #{ids.join(',')})")
=> [100, 1, 6]
For new Version
>> WordDo...
When to Redis? When to MongoDB? [closed]
...le u ON s.UserID = u.UserID WHERE u.Username = Simon and store the result, 100, as SET user:Simon:lingots = 100. Then when you award Simon 5 lingots, you read user:Simon:lingots = 100, SET user:Simon:lingots = 105, and UPDATE Store s INNER JOIN UserProfile u ON s.UserID = u.UserID SET s.Lingots = 1...