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Firefox Add-on RESTclient - How to input POST parameters?
... section of the Firefox plugin to have a “name” = “Content-Type” and “value” = “application/x-www-form-urlencoded”
Now, you are able to submit parameter like “name=mynamehere&title=TA” in the “request body” text area field
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How do I serialize a C# anonymous type to a JSON string?
... i a non-asp.net project (console application)?
– Alxandr
Jul 27 '10 at 0:22
4
@Alxandr: You woul...
How to do SQL Like % in Linq?
... answered May 7 '09 at 16:45
andleerandleer
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Android-java- How to sort a list of objects by a certain value within the object
...r.
See here, this may be of some help - When should a class be Comparable and/or Comparator?
Try this -
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
public class TestSort {
public static void main(String args[]){
ToSort toSort1 = new ToSort(new ...
MVC4 style bundle giving 403
...f my bundles seem to have an invalid URL in the browser (ending with a /), and IIS gives a 403 forbidden error, as if trying to list a folder's contents.
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Mockito test a void method throws an exception
...ct).methodReturningVoid(...);
^
and NOT use:
doThrow(new Exception()).when(mockedObject.methodReturningVoid(...));
^
This is explained in the documentation
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Is there a function to deselect all text using JavaScript?
...elements. For form-fields (like textarea), this method doesn't work in IE9 and FF5.
– Šime Vidas
Jul 3 '11 at 13:37
1
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Do you need to use path.join in node.js?
... case since back in the DOS days). The only real issue is that Windows command-line processors (or, more specifically, Windows-native command-line utilities) tend to interpret forward slashes as option specifiers rather than path components. Therefore, you need a backslashed path if you need to pass...
Server.MapPath(“.”), Server.MapPath(“~”), Server.MapPath(@“\”), ...
...tween Server.MapPath(".") , Server.MapPath("~") , Server.MapPath(@"\") and Server.MapPath("/") ?
3 Answers
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python .replace() regex [duplicate]
I am trying to do a grab everything after the "" tag and delete it, but my code doesn't seem to be doing anything. Does .replace() not support regex?
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